Learn › Class 9 CBSE · Science › Motion
Motion — Class 9 CBSE Science MCQs with Solutions
Free Class 9 CBSE Science Motion MCQs with step-by-step solutions. Practise online on Prepizo — no login needed.
▶ Practise Motion online (free)
Sample questions with solutions
Q1 — easy
Vector quantity representing shortest straight-line distance from initial to final position is:
A. Distance
B. Displacement ✓ Correct
C. Speed
D. Acceleration
Solution: Displacement is the shortest directed path vector between initial and final points.
Q2 — easy
SI unit of acceleration is:
A. m/s
B. m/s² ✓ Correct
C. km/h
D. m·s
Solution: Acceleration = Rate of change of velocity = (m/s)/s = m/s².
Q3 — easy
An object moving with uniform speed along a circular track is undergoing:
A. Uniform linear motion
B. Accelerated motion (direction changes continuously) ✓ Correct
C. Motion with zero acceleration
D. Rest
Solution: Direction changes continuously in circular paths, creating centripetal acceleration.
Q4 — easy
Slope of a Distance-Time graph represents the object's:
A. Acceleration
B. Speed / Velocity ✓ Correct
C. Displacement
D. Force
Solution: Slope of distance-time graph = Δs / Δt = Speed.
Q5 — easy
First equation of uniform accelerated motion is:
A. s = ut + ½at²
B. v = u + at ✓ Correct
C. v² − u² = 2as
D. v = u/t
Solution: v = u + at.
Q6 — easy
Second equation of motion relating displacement, initial velocity, time, and acceleration is:
A. v = u + at
B. s = ut + ½at² ✓ Correct
C. v² − u² = 2as
D. s = (u+v)t
Solution: s = ut + ½at².
Q7 — easy
Third equation of motion relating final velocity v, initial velocity u, acceleration a, and displacement s is:
A. v² − u² = 2as ✓ Correct
B. s = ut + ½at²
C. v = u + at
D. v² + u² = as
Solution: v² − u² = 2as.
Q8 — easy
An athlete completes one round of a circular track of radius R. Total displacement is:
A. 2πR
B. πR
C. Zero ✓ Correct
D. 2R
Solution: Initial and final positions coincide, so displacement = 0.
Q9 — easy
A car accelerates uniformly from 18 km/h to 36 km/h in 5 seconds. Its acceleration in m/s² is:
A. 1 m/s² ✓ Correct
B. 2 m/s²
C. 3 m/s²
D. 0.5 m/s²
Solution: 18 km/h = 5 m/s; 36 km/h = 10 m/s. a = (10 − 5)/5 = 1 m/s².
Q10 — easy
Distance covered by a body dropping from rest under gravity in 2 seconds is: (g = 10 m/s²)
A. 10 m
B. 20 m ✓ Correct
C. 40 m
D. 5 m
Solution: s = (0)(2) + ½(10)(2)² = 20 m.
Q11 — easy
Slope of a Velocity-Time graph represents:
A. Speed
B. Acceleration ✓ Correct
C. Displacement
D. Momentum
Solution: Slope of v-t graph = Δv / Δt = Acceleration.
Q12 — easy
Odometer of an automobile measures:
A. Instantaneous speed
B. Distance covered ✓ Correct
C. Acceleration
D. Fuel level
Solution: Odometers measure total distance traveled.
Q13 — easy
If a body moves with uniform velocity, its acceleration is:
A. Constant positive
B. Zero ✓ Correct
C. Negative
D. Infinite
Solution: Velocity remains constant (Δv = 0), so acceleration = 0.
Q14 — medium
Area enclosed under a Velocity-Time graph and time axis represents total:
A. Acceleration
B. Distance / Displacement ✓ Correct
C. Speed
D. Average velocity
Solution: Area under v-t graph = Velocity × Time = Displacement.
Q15 — medium
Convert speed of 90 km/h into m/s:
A. 20 m/s
B. 25 m/s ✓ Correct
C. 30 m/s
D. 15 m/s
Solution: 90 × (5/18) = 25 m/s.