Acceleration — Homi Bhabha Exam Physics MCQs with Solutions
Free Homi Bhabha Exam Physics Acceleration MCQs with step-by-step solutions (6 questions). Part of Motion & Kinematics. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Acceleration · medium · numerical
A car's velocity increases uniformly from 5 m/s to 25 m/s in 4 s. Its acceleration is:
A. 6.25 m/s²
B. 20 m/s²
C. 7.5 m/s²
D. 5 m/s² ✓ Correct
Solution: $a = \dfrac{v - u}{t} = \dfrac{25 - 5}{4} = 5$ m/s².
Q2 — Acceleration · hard · numerical
A car moving at 90 km/h is brought to rest in 5 s. Its retardation is:
A. 25 m/s²
B. 4.5 m/s²
C. 18 m/s²
D. 5 m/s² ✓ Correct
Solution: Convert: $90$ km/h $= 25$ m/s; retardation $= \dfrac{25}{5} = 5$ m/s² (18 m/s² comes from forgetting to convert km/h).
Q3 — Acceleration · medium · theory
When the acceleration of a body acts opposite to its direction of motion, the body:
A. moves with uniform velocity
B. slows down (retardation) ✓ Correct
C. stops instantly
D. speeds up
Solution: Acceleration opposite to motion reduces the speed — this is retardation (negative acceleration).
Q4 — Acceleration · medium · numerical
A body is dropped from rest. Taking $g = 10$ m/s², its velocity after 3 s of free fall is:
A. 30 m/s ✓ Correct
B. 10 m/s
C. 3.3 m/s
D. 90 m/s
Solution: $v = u + gt = 0 + 10 \times 3 = 30$ m/s.
Q5 — Acceleration · hard · theory
Assertion (A): A body thrown vertically upward has zero velocity but non-zero acceleration at its highest point. Reason (R): At the highest point gravity still acts on the body.
A. A is true but R is false
B. A is false but R is true
C. Both A and R are true and R is the correct explanation of A ✓ Correct
D. Both A and R are true but R is NOT the correct explanation of A
Solution: At the top $v = 0$, but gravity ($g$) still acts downward, so acceleration is non-zero — R correctly explains A.
Q6 — Acceleration · hard · numerical
On a velocity–time graph, a straight line rises from 0 to 20 m/s in 4 s. The acceleration represented is:
A. 80 m/s²
B. 0.2 m/s²
C. 5 m/s² ✓ Correct
D. 4 m/s²
Solution: On a v–t graph, acceleration = slope $= \dfrac{20 - 0}{4} = 5$ m/s².