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Relative Motion in 2D — IISER Physics MCQs with Solutions

Free IISER Physics Relative Motion in 2D MCQs with step-by-step solutions (20 questions). Part of Motion in 2D. Practise online on Prepizo — no login needed.

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Questions with solutions

Q1 — Relative Motion in 2D · easy · numerical
Ship P sails due east at 9 km/h while ship Q sails due north at 12 km/h. What is the magnitude of the velocity of Q relative to P?
A. 3 km/h
B. 12 km/h
C. 21 km/h
D. 15 km/h  ✓ Correct
Solution: v_QP = v_Q − v_P has perpendicular components 12 km/h (north) and 9 km/h (west), so |v_QP| = √(9² + 12²) = 15 km/h.
Q2 — Relative Motion in 2D · easy · numerical
Drone A flies due east at 54 km/h and drone B flies due north at 20 m/s. What is the speed of B relative to A?
A. 35 m/s
B. 25 m/s  ✓ Correct
C. 20 m/s
D. 5 m/s
Solution: 54 km/h = 15 m/s; the relative velocity has perpendicular components 15 m/s and 20 m/s, so |v_BA| = √(15² + 20²) = 25 m/s.
Q3 — Relative Motion in 2D · easy · numerical
Trolley A moves due east at 12 m/s and trolley B moves due north at 12 m/s. In which direction does B appear to move as seen from A?
A. 45° west of north (towards the north-west)  ✓ Correct
B. Towards the south-west
C. Due north
D. 45° east of north (towards the north-east)
Solution: v_BA = v_B − v_A = 12 ĵ − 12 î (m/s): equal components towards the north and the west, which points 45° west of north.
Q4 — Relative Motion in 2D · easy · numerical
Two insects leave the same crumb at the same moment, one crawling east at 0.9 cm/s and the other north at 1.2 cm/s. How far apart are they after 6 s?
A. 12.6 cm
B. 9 cm  ✓ Correct
C. 1.8 cm
D. 4.5 cm
Solution: Their separation grows at the relative speed √(0.9² + 1.2²) = 1.5 cm/s, so after 6 s they are 1.5 × 6 = 9 cm apart.
Q5 — Relative Motion in 2D · easy · numerical
Probe A moves due east at 10 m/s and probe B moves due north at 24 m/s. What is the speed of A relative to B?
A. 26 m/s  ✓ Correct
B. 34 m/s
C. 14 m/s
D. 17 m/s
Solution: The velocities are perpendicular, so |v_AB| = √(10² + 24²) = √676 = 26 m/s.
Q6 — Relative Motion in 2D · easy · numerical
Robot A has velocity 7 î + 2 ĵ (m/s) and robot B has velocity −2 î − 10 ĵ (m/s). What is the speed of A relative to B?
A. 12 m/s
B. 9 m/s
C. 21 m/s
D. 15 m/s  ✓ Correct
Solution: v_AB = v_A − v_B = (7 − (−2), 2 − (−10)) = (9, 12) m/s, so |v_AB| = √(81 + 144) = 15 m/s.
Q7 — Relative Motion in 2D · easy · numerical
Two spheres are rolled from the same corner of a hall at the same moment, one east at 2.1 m/s and the other north at 2.8 m/s. How far apart are they after 10 s?
A. 17.5 m
B. 49 m
C. 35 m  ✓ Correct
D. 25 m
Solution: Relative speed = √(2.1² + 2.8²) = 3.5 m/s, so separation after 10 s = 3.5 × 10 = 35 m.
Q8 — Relative Motion in 2D · easy · numerical
Two ships leave the same port together, one heading due east at 16 km/h and the other due north at 30 km/h. How far apart are they after 30 minutes?
A. 34 km
B. 23 km
C. 17 km  ✓ Correct
D. 8.5 km
Solution: Relative speed = √(16² + 30²) = 34 km/h; in 0.5 h the separation is 34 × 0.5 = 17 km.
Q9 — Relative Motion in 2D · medium · numerical
Two drones take off from the same helipad at the same moment, each flying at 20 m/s, with their directions 60° apart. How far apart are they after 4 s?
A. 40√3 ≈ 69.3 m
B. 160 m
C. 40 m
D. 80 m  ✓ Correct
Solution: For equal speeds v at angle θ, |v_rel| = 2v sin(θ/2) = 2 × 20 × sin 30° = 20 m/s; separation = 20 × 4 = 80 m.
Q10 — Relative Motion in 2D · medium · numerical
Two ships leave the same port at the same time, one due east at 21 km/h and the other due north at 28 km/h. After how much time are they 70 km apart?
A. 2.5 h
B. 2 h  ✓ Correct
C. 1 h
D. 3.5 h
Solution: The separation grows at √(21² + 28²) = 35 km/h, so t = 70 / 35 = 2 h.
Q11 — Relative Motion in 2D · medium · numerical
Trolley A is 60 m west of a junction moving east at 12 m/s, and trolley B is 45 m south of the same junction moving north at 9 m/s. How far apart are they 2 s later?
A. 63 m
B. 36 m
C. 45 m  ✓ Correct
D. 75 m
Solution: At t = 2 s, A is 60 − 24 = 36 m west and B is 45 − 18 = 27 m south of the junction; separation = √(36² + 27²) = √2025 = 45 m.
Q12 — Relative Motion in 2D · medium · numerical
Drone B is 65 m due north of drone A. A flies due east at 24 m/s and B flies due south at 10 m/s. What is the minimum distance between them? (Both fly at the same height.)
A. 39 m
B. 25 m
C. 65 m
D. 60 m  ✓ Correct
Solution: Relative to A, B moves with velocity (−24, −10) m/s, |v_rel| = 26 m/s; the closest approach is the perpendicular distance 65 × (24/26) = 60 m.
Q13 — Relative Motion in 2D · medium · numerical
Probe B is 125 m due north of probe A. A moves due east at 20 m/s and B moves due south at 15 m/s. After how much time is the separation between them minimum?
A. 2.5 s
B. 4 s
C. 5 s
D. 3 s  ✓ Correct
Solution: Relative to A, B has velocity (−20, −15) m/s with |v_rel| = 25 m/s; time of closest approach = (125 × 15)/25² = 1875/625 = 3 s.
Q14 — Relative Motion in 2D · medium · numerical
An observer on trolley A, moving due east at 21 m/s, sees ball B moving due north at 28 m/s. What is the true speed of B relative to the ground?
A. 28 m/s
B. 7 m/s
C. 35 m/s  ✓ Correct
D. 49 m/s
Solution: v_B = v_A + v_BA = (21, 0) + (0, 28) = (21, 28) m/s, so the true speed is √(441 + 784) = 35 m/s.
Q15 — Relative Motion in 2D · medium · numerical
Sphere A rolls due north at 14 m/s and sphere B rolls due east at 14 m/s. What is the magnitude of the velocity of B relative to A?
A. 14√2 ≈ 19.8 m/s  ✓ Correct
B. 14 m/s
C. 7√2 ≈ 9.9 m/s
D. 28 m/s
Solution: v_BA = (14, −14) m/s (east and south components), so |v_BA| = 14√2 ≈ 19.8 m/s.
Q16 — Relative Motion in 2D · medium · numerical
Robot A is 80 m west of a crossing, moving east at 10 m/s. Robot B is 96 m south of the crossing and starts at the same moment. At what speed must B move north so that both reach the crossing together?
A. 15 m/s
B. 10 m/s
C. 12 m/s  ✓ Correct
D. 9.6 m/s
Solution: A reaches the crossing in 80/10 = 8 s, so B needs 96/8 = 12 m/s.
Q17 — Relative Motion in 2D · medium · numerical
Two insects leave the same grain at the same moment, each crawling at 2.4 cm/s, with their paths 60° apart. How far apart are they after 5 s?
A. 24 cm
B. 12 cm  ✓ Correct
C. 6 cm
D. 12√3 ≈ 20.8 cm
Solution: |v_rel| = 2v sin(θ/2) = 2 × 2.4 × sin 30° = 2.4 cm/s, so separation = 2.4 × 5 = 12 cm.
Q18 — Relative Motion in 2D · medium · numerical
Drone A is 46 m east of a checkpoint, flying west at 10 m/s; drone B is 60 m north of the checkpoint, flying south at 10 m/s. How far apart are the drones 3 s later?
A. 46 m
B. 26 m
C. 14 m
D. 34 m  ✓ Correct
Solution: At t = 3 s, A is 46 − 30 = 16 m east and B is 60 − 30 = 30 m north of the checkpoint; separation = √(16² + 30²) = 34 m.
Q19 — Relative Motion in 2D · medium · numerical
Probe A has velocity 10 î − 6 ĵ (m/s) and probe B has velocity −8 î + 12 ĵ (m/s). What is the speed of A relative to B?
A. 18√2 ≈ 25.5 m/s  ✓ Correct
B. 18 m/s
C. 36 m/s
D. 6√2 ≈ 8.5 m/s
Solution: v_AB = (10 − (−8), −6 − 12) = (18, −18) m/s, so |v_AB| = 18√2 ≈ 25.5 m/s.
Q20 — Relative Motion in 2D · medium · numerical
Ball A is 45 m west of a corner mark, rolling east at 9 m/s. Ball B starts from the mark at the same moment, rolling north at 12 m/s. How far apart are the balls 3 s later?
A. 18 m
B. 18√5 ≈ 40.2 m  ✓ Correct
C. 54 m
D. 36 m
Solution: At t = 3 s, A is 45 − 27 = 18 m west of the mark and B is 36 m north of it; separation = √(18² + 36²) = √1620 = 18√5 ≈ 40.2 m.