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Electronegativity, Reactivity & Anomalous Properties — JEE Main Chemistry MCQs with Solutions

Free JEE Main Chemistry Electronegativity, Reactivity & Anomalous Properties MCQs with step-by-step solutions (40 questions). Part of Classification of Elements and Periodicity. Practise online on Prepizo — no login needed.

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Questions with solutions

Q1 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
Electronegativity is the tendency of an atom in a molecule to:
A. Lose electrons
B. Gain electrons as an isolated atom
C. Attract the shared pair of bonding electrons towards itself  ✓ Correct
D. Emit radiation
Solution: It is a relative measure of an atom's pull on the shared electrons in a covalent bond.
Q2 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
Across a period, electronegativity generally:
A. Stays constant
B. First increases then decreases
C. Decreases
D. Increases  ✓ Correct
Solution: Rising Z_eff and smaller size increase the pull on shared electrons.
Q3 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
Down a group, electronegativity generally:
A. Decreases  ✓ Correct
B. Increases
C. Stays constant
D. First decreases then increases
Solution: Larger size and shielding reduce the attraction for shared electrons.
Q4 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
The most electronegative element is:
A. Fluorine  ✓ Correct
B. Oxygen
C. Caesium
D. Chlorine
Solution: F has the highest electronegativity (4.0 on the Pauling scale).
Q5 — Electronegativity, Reactivity & Anomalous Properties · medium · theory
The Mulliken electronegativity is defined as:
A. χ_M = (IE + EA)/2  ✓ Correct
B. χ_M = IE − EA
C. χ_M = (IE − EA)/2
D. χ_M = IE × EA
Solution: Mulliken took the average of ionization energy and electron affinity (in eV).
Q6 — Electronegativity, Reactivity & Anomalous Properties · hard · theory
On the Pauling scale, the electronegativity difference is related to the extra bond energy Δ by:
A. |χ_A − χ_B| = Δ/0.208
B. |χ_A − χ_B| = 0.208 Δ²
C. |χ_A − χ_B| = 0.208√Δ (Δ in kcal/mol)  ✓ Correct
D. |χ_A − χ_B| = 0.208 Δ
Solution: Pauling: |χ_A − χ_B| = 0.208√Δ, where Δ is the resonance (ionic) contribution to the bond energy.
Q7 — Electronegativity, Reactivity & Anomalous Properties · medium · theory
The difference between electronegativity and electron gain enthalpy is that electronegativity:
A. Is a property of a bonded atom (relative), while electron gain enthalpy is for an isolated gaseous atom  ✓ Correct
B. Is measured in kJ/mol
C. Applies only to metals
D. Is always positive energy
Solution: Electronegativity is a relative, dimensionless bonding property; Δₑ𝓰H is a measurable enthalpy for a free atom.
Q8 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
A diagonal relationship exists between pairs such as:
A. F–Cl, O–S
B. C–N, N–O
C. Li–Mg, Be–Al, B–Si  ✓ Correct
D. Na–K, Ca–Ba
Solution: Diagonally placed elements show similar properties (Li–Mg, Be–Al, B–Si).
Q9 — Electronegativity, Reactivity & Anomalous Properties · medium · theory
The cause of the diagonal relationship is the similarity in:
A. Charge/radius ratio (polarising power)  ✓ Correct
B. Number of neutrons
C. Atomic mass
D. Colour of compounds
Solution: Moving right increases charge and moving down increases size; diagonally these offset to give similar charge/size ratios.
Q10 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
Across a period, metallic character:
A. Stays constant
B. First increases then decreases
C. Increases
D. Decreases (non-metallic character increases)  ✓ Correct
Solution: Higher IE and electronegativity across a period make elements less metallic.
Q11 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
Down a group, metallic character:
A. Increases  ✓ Correct
B. First decreases then increases
C. Decreases
D. Stays constant
Solution: Lower IE down a group makes it easier to lose electrons — more metallic.
Q12 — Electronegativity, Reactivity & Anomalous Properties · medium · theory
The nature of oxides across a period changes in the order:
A. Basic → amphoteric → acidic  ✓ Correct
B. Amphoteric → basic → acidic
C. Acidic → amphoteric → basic
D. Basic → acidic → neutral
Solution: e.g. Na₂O (basic) → Al₂O₃ (amphoteric) → Cl₂O₇ (acidic).
Q13 — Electronegativity, Reactivity & Anomalous Properties · medium · theory
Down a group, the basic character of the oxides/hydroxides of the elements:
A. Increases  ✓ Correct
B. Decreases
C. Becomes neutral
D. Stays constant
Solution: Greater metallic character down a group gives more basic oxides/hydroxides.
Q14 — Electronegativity, Reactivity & Anomalous Properties · medium · theory
The valency of an element with respect to hydrogen for group 15 is:
A. 1
B. 3  ✓ Correct
C. 2
D. 5
Solution: H-valency = 8 − group(old, i.e. 8 − 5) = 3, e.g. NH₃.
Q15 — Electronegativity, Reactivity & Anomalous Properties · easy · theory
Al₂O₃ is classified as ______ because it reacts with both acids and bases:
A. Basic
B. Neutral
C. Acidic
D. Amphoteric  ✓ Correct
Solution: Amphoteric oxides (Al₂O₃, ZnO, PbO) react with both acids and bases.
Q16 — Electronegativity, Reactivity & Anomalous Properties · hard · theory
The Allred–Rochow scale of electronegativity is based on the:
A. Atomic volume
B. Bond energy differences
C. Average of IE and EA
D. Electrostatic force exerted by the nucleus on the valence electrons  ✓ Correct
Solution: Allred–Rochow: χ ∝ Z_eff/r², the effective nuclear pull on a valence electron.
Q17 — Electronegativity, Reactivity & Anomalous Properties · easy · numerical
The correct increasing order of electronegativity for C, N, O, F is:
A. C < N < O < F  ✓ Correct
B. F < O < N < C
C. O < N < C < F
D. N < C < O < F
Solution: Electronegativity increases across a period: C < N < O < F.
Q18 — Electronegativity, Reactivity & Anomalous Properties · medium · numerical
The Mulliken electronegativity (in eV) of an atom with IE = 17.4 eV and EA = 3.6 eV is:
A. 13.8 eV
B. 6.9 eV
C. 21.0 eV
D. 10.5 eV  ✓ Correct
Solution: χ_M = (IE + EA)/2 = (17.4 + 3.6)/2 = 10.5 eV.
Q19 — Electronegativity, Reactivity & Anomalous Properties · hard · numerical
For a bond A–B with an ionic resonance energy Δ = 100 kcal/mol, the electronegativity difference (Pauling) is:
A. 0.208
B. 20.8
C. 2.08  ✓ Correct
D. 1.04
Solution: |χ_A − χ_B| = 0.208√Δ = 0.208 × 10 = 2.08.
Q20 — Electronegativity, Reactivity & Anomalous Properties · easy · numerical
The correct decreasing order of electronegativity for F, Cl, Br, I is:
A. F > Br > Cl > I
B. F > Cl > Br > I  ✓ Correct
C. I > Br > Cl > F
D. Cl > F > Br > I
Solution: Electronegativity decreases down group 17: F > Cl > Br > I.
Q21 — Electronegativity, Reactivity & Anomalous Properties · easy · numerical
Which oxide is amphoteric?
A. Al₂O₃  ✓ Correct
B. Cl₂O₇
C. Na₂O
D. MgO
Solution: Al₂O₃ reacts with both acids and bases; Na₂O/MgO are basic, Cl₂O₇ is acidic.
Q22 — Electronegativity, Reactivity & Anomalous Properties · medium · numerical
Which oxide is the most acidic?
A. Al₂O₃
B. Na₂O
C. MgO
D. Cl₂O₇  ✓ Correct
Solution: Acidic character rises across a period; Cl₂O₇ (Cl in +7) is strongly acidic.
Q23 — Electronegativity, Reactivity & Anomalous Properties · hard · numerical
For a bond with Δ = 25 kcal/mol, the Pauling electronegativity difference is:
A. 5.2
B. 0.52
C. 1.04  ✓ Correct
D. 10.4
Solution: 0.208√25 = 0.208 × 5 = 1.04.
Q24 — Electronegativity, Reactivity & Anomalous Properties · medium · numerical
The valency of sulphur (group 16) with respect to oxygen (its maximum) is:
A. 2
B. 6  ✓ Correct
C. 4
D. 8
Solution: Maximum oxidation state w.r.t. oxygen = group number = 6 (e.g. SO₃, H₂SO₄).
Q25 — Electronegativity, Reactivity & Anomalous Properties · easy · numerical
The valency of nitrogen with respect to hydrogen is:
A. 5
B. 3  ✓ Correct
C. 2
D. 1
Solution: H-valency = 8 − 5 = 3 (NH₃).
Q26 — Electronegativity, Reactivity & Anomalous Properties · easy · numerical
The pair showing a diagonal relationship is:
A. Be and Al  ✓ Correct
B. Be and Mg
C. B and Al
D. Na and Mg
Solution: Be (group 2) and Al (group 13, next period) are diagonally related.
Q27 — Electronegativity, Reactivity & Anomalous Properties · medium · numerical
The Mulliken electronegativity of an atom with IE = 11.3 eV and EA = 1.3 eV is:
A. 5.0 eV
B. 12.6 eV
C. 10.0 eV
D. 6.3 eV  ✓ Correct
Solution: χ_M = (11.3 + 1.3)/2 = 6.3 eV.
Q28 — Electronegativity, Reactivity & Anomalous Properties · medium · numerical
Across period 3, the increasing order of acidic character of oxides is:
A. SO₃ < SiO₂ < Al₂O₃ < Na₂O
B. SiO₂ < SO₃ < Na₂O < Al₂O₃
C. Na₂O < Al₂O₃ < SiO₂ < SO₃  ✓ Correct
D. Al₂O₃ < Na₂O < SO₃ < SiO₂
Solution: Oxides go basic → amphoteric → acidic: Na₂O < Al₂O₃ < SiO₂ < SO₃.
Q29 — Electronegativity, Reactivity & Anomalous Properties · easy · numerical
The most metallic element among Na, Mg, Al, Si is:
A. Mg
B. Si
C. Al
D. Na  ✓ Correct
Solution: Metallic character decreases across a period, so Na (leftmost) is most metallic.
Q30 — Electronegativity, Reactivity & Anomalous Properties · medium · numerical
The least metallic (most non-metallic) among P, S, Cl, Ar is:
A. Ar (or Cl among reactive ones)  ✓ Correct
B. Na
C. P
D. S
Solution: Non-metallic character increases across the period; the noble gas Ar/halogen Cl are most non-metallic.