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Centre of Mass & Collision — JEE Main Physics MCQs with Solutions
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Sample questions with solutions
Q1 — medium · theory
A nucleus at rest disintegrates into two 24-5. A simple pendulum of length 1 m has a
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q2 — medium · theory
Two blocks of masses 10 kg and 30 kg are
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q3 — medium · theory
(1) 24-2. (4) ANSWER KEY 24-4. (2) 24-5. (2)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q4 — medium · theory
(4) 23-2. (4) 22-1. (3) 22-2. (2)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q5 — medium · numerical
By conservation of momentum Pi = Pf (Collision)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q6 — medium · theory
1: 2 m
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q7 — medium · theory
The velocities will be interchanged after
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q8 — medium · theory
vav t 2.5 m / s
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q9 — medium · theory
3h 1 gt2 t 3h
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q10 — medium · theory
smaller nuclei with their masses in the ratio 23-2. wooden bob of mass 1 kg. It is struck by a
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q11 — medium · theory
2
A. 4 cm towards the 10 kg block ✓ Correct
B. 2 cm away from the 10 kg block
C. 2 cm towards the 10 kg block
D. 4 cm away from the 10 kg block
Q12 — medium · numerical
p =p (0.1) (400) = (0.1 + 3.9)v
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q13 — medium · theory
Momentum will remain conserve Apply equation of motion,
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q14 — medium · numerical
collision = 2gh
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q15 — medium · theory
acm m1a1 m2a2 dm 500 – 103 10 103 20
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q16 — medium · theory
Time of collision
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q17 — medium · numerical
Loss of K.E = work done against retarding
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q18 — medium · theory
23-3.
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q19 — medium · numerical
A large block of wood of mass M = 5.99 kg out at a relative speed of 500 ms–1 with
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q20 — medium · theory
As shown in fig. when a spherical cavity 20-6. CENTRE OF MASS
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q21 — medium · theory
(3) 22-4. (2) 24-3. (4) 21-2. (4) 21-3. (3)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q22 — medium · theory
(1) 20-4. (4) 21-1. (3) 20-6. (4) 24-6. 15
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q23 — medium · numerical
O=m u m u v 0.1 400 10 m/s
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q24 — medium · theory
of 2: 1. After disintegration they will move :- bullet of mass 10 kg moving with a speed
A. In opposite directions with speed in the into the bob. The height to which the bob ✓ Correct
B. In opposite directions with speed in the 10 m/s ) [JEE-Main_010224_(S1)]
C. In the same direction with same speed. (3) 0.35 m (4) 0.40 m
D. In opposite directions with the same A machine gun of mass 10 kg fires 20 g
Q25 — medium · theory
CENTRE OF MASS
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q26 — medium · theory
A rubber ball is released from a height of 5 time another particle of the same mass is
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q27 — medium · numerical
(4) (R2 + R – 1) (2 – R) = 1
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q28 — medium · theory
[JEE-Main_310124_(S1)] After collision, A moves with a velocity
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q29 — medium · theory
(4) 21-5. (2) 23-3. (3) 20-1. (1) 20-2. (4)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q30 — medium · theory
V1 2 g h
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D