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Velocity — JEE Main Physics MCQs with Solutions

Free JEE Main Physics Velocity MCQs with step-by-step solutions (36 questions). Part of Motion in 1 Dimension. Practise online on Prepizo — no login needed.

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Questions with solutions

Q1 — Velocity · easy · theory
Velocity is a
A. Scalar quantity
B. Unit
C. Vector quantity  ✓ Correct
D. Pure number
Solution: Velocity is speed WITH direction — a vector.
Q2 — Velocity · easy · theory
Average velocity is defined as
A. Displacement ÷ time  ✓ Correct
B. Speed × time
C. Distance ÷ time
D. Acceleration × time
Solution: $\bar{\vec v} = \frac{\Delta\vec r}{\Delta t}$ — it uses displacement, not path length.
Q3 — Velocity · medium · theory
A jogger returns to her starting point after a $30$-minute run. Her average velocity is
A. Negative
B. Zero  ✓ Correct
C. Equal to her average speed
D. Maximum
Solution: Round trip $\Rightarrow$ zero displacement $\Rightarrow$ zero average velocity (average speed is non-zero).
Q4 — Velocity · easy · theory
Instantaneous velocity is given by
A. $\frac{d^2x}{dt^2}$
B. $x\cdot t$
C. $\frac{dx}{dt}$  ✓ Correct
D. $\frac{x}{t}$
Solution: Velocity is the time derivative of position.
Q5 — Velocity · easy · numerical
The position of a particle is $x = 3t^2$ (metres, seconds). Its velocity at $t = 2$ s is
A. $24$ m/s
B. $6$ m/s
C. $12$ m/s  ✓ Correct
D. $3$ m/s
Solution: $v = \frac{dx}{dt} = 6t$; at $t = 2$: $v = 12$ m/s.
Q6 — Velocity · easy · theory
A body moving with uniform velocity has
A. Constant non-zero acceleration
B. Changing direction
C. Zero acceleration  ✓ Correct
D. Increasing speed
Solution: Uniform velocity means neither the magnitude nor direction changes — so $a = 0$.
Q7 — Velocity · easy · theory
In one-dimensional motion, velocity
A. Is always positive
B. Can be positive, negative or zero  ✓ Correct
C. Cannot be zero
D. Is always equal to speed
Solution: The sign encodes direction along the axis.
Q8 — Velocity · easy · numerical
The position of a particle is $x = 5 + 4t$ (metres, seconds). Its velocity is
A. $20$ m/s
B. $5$ m/s
C. $9$ m/s
D. $4$ m/s  ✓ Correct
Solution: $v = \frac{dx}{dt} = 4$ m/s — uniform velocity (the 5 m is just the starting position).
Q9 — Velocity · medium · theory
The magnitude of average velocity compared with average speed is
A. Greater than or equal to it
B. Always equal
C. Always double
D. Less than or equal to it  ✓ Correct
Solution: $|\bar{\vec v}| = \frac{|\text{displacement}|}{t} \leq \frac{\text{distance}}{t} = $ average speed.
Q10 — Velocity · easy · theory
Can the velocity of a body change while its speed remains constant?
A. No, never
B. Only at rest
C. Yes — if the direction changes (e.g. circular motion)  ✓ Correct
D. Only if it accelerates in a straight line
Solution: Velocity is a vector: changing direction alone changes velocity.
Q11 — Velocity · medium · theory
Two trains run at $60$ km/h and $40$ km/h in OPPOSITE directions. The magnitude of their relative velocity is
A. $50$ km/h
B. $2400$ km/h
C. $20$ km/h
D. $100$ km/h  ✓ Correct
Solution: Opposite directions: relative speed $= 60 + 40 = 100$ km/h.
Q12 — Velocity · medium · theory
Two cars travel in the same direction at $80$ km/h and $50$ km/h. The velocity of the faster car relative to the slower one is
A. $130$ km/h
B. $30$ km/h forward  ✓ Correct
C. Zero
D. $30$ km/h backward
Solution: $\vec v_{rel} = 80 - 50 = 30$ km/h in the direction of motion.
Q13 — Velocity · easy · theory
A particle moves as $x = t^3 - 3t^2$ (metres, seconds). Its velocity is zero at the non-zero time $t =$
A. $2$ s  ✓ Correct
B. $3$ s
C. $1.5$ s
D. $1$ s
Solution: $v = 3t^2 - 6t = 3t(t-2) = 0 \Rightarrow t = 0$ or $t = 2$ s.
Q14 — Velocity · medium · theory
A particle at rest necessarily has
A. All of these zero
B. Zero position
C. Zero velocity  ✓ Correct
D. Zero acceleration
Solution: Rest means velocity zero; its position can be anywhere, and acceleration may even be non-zero momentarily.
Q15 — Velocity · easy · numerical
A body moves at $5$ m/s for $10$ s, then stays at rest for $10$ s (no reversal). Its average velocity over the $20$ s is
A. $2.5$ m/s  ✓ Correct
B. $5$ m/s
C. $1$ m/s
D. Zero
Solution: Displacement $= 50$ m in $20$ s: $\bar v = 2.5$ m/s.
Q16 — Velocity · easy · theory
A negative velocity in one-dimensional motion means the particle is
A. Accelerating
B. Moving in the negative direction of the axis  ✓ Correct
C. At rest
D. Slowing down
Solution: The sign of $v$ gives direction only — it says nothing about speeding up or slowing down.
Q17 — Velocity · easy · theory
A car moving east at $40$ km/h turns around and moves west at $40$ km/h. The magnitude of its change in velocity is
A. $80$ km/h  ✓ Correct
B. $40$ km/h
C. $40\sqrt{2}$ km/h
D. Zero
Solution: $\Delta v = (-40) - (+40) = -80$: magnitude $80$ km/h, directed west.
Q18 — Velocity · easy · theory
The slope of the tangent to a position–time graph at an instant gives
A. Instantaneous velocity  ✓ Correct
B. Average velocity
C. Acceleration
D. Distance
Solution: $v = \frac{dx}{dt}$ — geometrically the slope of the tangent at that point.
Q19 — Velocity · easy · numerical
A man walks $100$ m east in $50$ s, then $100$ m west in $50$ s. His average velocity for the whole trip is
A. Zero  ✓ Correct
B. $4$ m/s
C. $2$ m/s
D. $1$ m/s
Solution: Net displacement is zero, so average velocity $= 0$ (average speed is 2 m/s).
Q20 — Velocity · easy · theory
A body has uniform velocity if it covers
A. Equal distances only
B. Equal displacements in equal intervals of time  ✓ Correct
C. Equal distances in unequal times
D. Increasing displacements
Solution: Uniform velocity: same displacement (magnitude AND direction) every equal time interval.
Q21 — Velocity · medium · theory
The SI unit of velocity is
A. m/s  ✓ Correct
B. m
C. km/h
D. m/s²
Solution: Metre per second; km/h is common but not the SI unit.
Q22 — Velocity · easy · theory
A lift ascends $10$ m in $5$ s at constant rate. Its velocity is
A. $50$ m/s
B. $2$ m/s downward
C. $2$ m/s upward  ✓ Correct
D. $0.5$ m/s
Solution: $v = \frac{10}{5} = 2$ m/s, directed upward.
Q23 — Velocity · easy · numerical
The position of a particle is $x = t^2 - 4t + 3$ (metres, seconds). Its velocity at $t = 1$ s is
A. $-4$ m/s
B. $2$ m/s
C. $-2$ m/s  ✓ Correct
D. Zero
Solution: $v = 2t - 4$; at $t=1$: $v = -2$ m/s (moving in the negative direction).
Q24 — Velocity · easy · theory
Average velocity equals instantaneous velocity when the motion is
A. Uniformly accelerated
B. Uniform (constant velocity)  ✓ Correct
C. Circular
D. Any motion
Solution: With constant velocity, every instant matches the average.
Q25 — Velocity · medium · theory
Two cars approach each other at $30$ km/h and $20$ km/h. Their relative speed of approach is
A. $50$ km/h  ✓ Correct
B. $25$ km/h
C. $600$ km/h
D. $10$ km/h
Solution: Head-on approach: speeds add, $30+20 = 50$ km/h.
Q26 — Velocity · easy · theory
A body moves with constant velocity $20$ m/s for $3$ s. Its displacement is
A. $23$ m
B. $6.7$ m
C. $20$ m
D. $60$ m  ✓ Correct
Solution: $s = vt = 20\times3 = 60$ m.
Q27 — Velocity · easy · theory
A position–time graph with negative slope indicates
A. Negative acceleration
B. The body at rest
C. Velocity in the negative direction  ✓ Correct
D. Impossible motion
Solution: Slope of $x$–$t$ IS velocity; a negative slope means $x$ is decreasing.
Q28 — Velocity · easy · theory
A particle reverses its direction of motion at the instant when
A. Its position is zero
B. Its velocity changes sign  ✓ Correct
C. Its acceleration is zero
D. Its speed is maximum
Solution: Direction reversal is exactly a sign change of velocity (passing through zero).
Q29 — Velocity · medium · theory
Can a body have zero velocity and non-zero acceleration at the same instant?
A. Yes — e.g. at the top of a vertical throw  ✓ Correct
B. Only in circular motion
C. Only at rest permanently
D. No, never
Solution: At the highest point $v = 0$ momentarily while $a = g$ still acts — the classic example.
Q30 — Velocity · medium · numerical
A particle covers displacement $\vec d_1 = 3\hat{i}$ m in $1$ s and then $\vec d_2 = 4\hat{j}$ m in the next $1$ s. The magnitude of its average velocity over the $2$ s is
A. $5$ m/s
B. $7$ m/s
C. $3.5$ m/s
D. $2.5$ m/s  ✓ Correct
Solution: Total displacement $= \sqrt{9+16} = 5$ m in $2$ s $\Rightarrow 2.5$ m/s.