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Semiconductors — JEE Main Physics MCQs with Solutions
Free JEE Main Physics Semiconductors MCQs with step-by-step solutions. Practise online on Prepizo — no login needed.
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Sample questions with solutions
Q1 — medium · theory
When a polaroid sheet is rotated between two 24-5. A microwave of wavelength 2.0 cm falls
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q2 — medium · theory
The interference pattern is obtained with two (1) 2D(d0 ) (2) 2 D a 0
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q3 — medium · theory
(4) 24-2. (1) ANSWER KEY 24-4. (1) WAVE OPTICS
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q4 — medium · theory
(1) 23-2. (3) 22-1. (2)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q5 — medium · numerical
Let I be intensity of unpolarised light incident 24-2. Δx =
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q6 — medium · numerical
Given, D = 1m WAVE OPTICS
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q7 — medium · numerical
1 4 I2 = I1 cos230º
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q8 — medium · theory
Fringe Width,
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q9 — medium · theory
23-1.
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q10 — medium · theory
IA I0 and we know that fringe width D
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q11 — medium · numerical
20-2. Phase difference = 2 optical path difference
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q12 — medium · numerical
7 Li 11 H 224He 24-8. Q = BEProduct − BERectant
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q13 — medium · theory
coherent light sources of intensity ratio 4 :1. ( d 2 a 2 ) ( d 2 a 2 )
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q14 — medium · theory
(2) 22-4. (3) 24-3. (1) 20-1. (1) 24-5. (3)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q15 — medium · theory
(1) 24-6. 10 23-3. (2) 24-8. 200 22-2. (2)
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q16 — medium · theory
150 21-5. 300
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q17 — medium · theory
C 2 5 0 WAVE OPTICS
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q18 — medium · theory
235 U 140 Ce 94 Zr n 1
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q19 — medium · theory
intensity will be maximum for a rotation of : 23-3. spread of the central maxima of the diffraction
A. 60º (2) 30º the slit, will be: [JEE-Main_010224_{S2}] ✓ Correct
B. 90º (4) 45º (1) 30º (2) 150º
C. 1/2 (2) 3/4 (1) 60 m (2) 48 m
D. 1/3 (4) 1/4 (3) 12 m (4) 36 m
Q20 — medium · theory
0 0 0 0
A. 3 (2) 4 (3) 2 (4) 1 the screen when light of a wavelength 700 nm ✓ Correct
B. 3 (2) 2 wave travels a path L1 through a medium of
C. 1.5 (4) 0.5 travels a path of length L2 through a medium of
D. 16 (2) 9 2 2 L2 L1
Q21 — medium · numerical
������ = Δx = × =
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q22 — medium · theory
7000 Å and 5500 Å is used to obtain 21-3.
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q23 — medium · theory
450 22-7. 2
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q24 — medium · theory
������ ������ 4 2
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q25 — medium · numerical
Energy released = 1 6 1023 200
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q26 — medium · theory
wavelength 6000 Å is used. The distance
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q27 — medium · theory
As shown in the figure, in Young's double slit
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q28 — medium · theory
interference pattern in Young's double slit An unpolarized light beam is incident on the
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q29 — medium · theory
4 23-7. 462 24-7. 2 22-6. 600 24-9. 0.20
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D
Q30 — medium · theory
24-10. Let intensity of light on screen due to each slit
A. Option A ✓ Correct
B. Option B
C. Option C
D. Option D