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Chemistry - 1 — MH-CET Full Length Paper MCQs with Solutions

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Sample questions with solutions

Q1 — easy
Which type of crystal defect decreases the density of an ionic crystalline solid?
A. Frenkel defect
B. Schottky defect  ✓ Correct
C. Interstitial defect
D. Metal excess defect
Solution: Schottky defect creates stoichiometric cation-anion vacancies, decreasing crystal density.
Q2 — easy
The boiling point elevation constant ($K_b$) of water is $0.52\text{ K}\cdot\text{kg}\cdot\text{mol}^{-1}$. The boiling point elevation of a $0.1\text{ m}$ aqueous solution of urea is:
A. $0.052^\circ\text{C}$  ✓ Correct
B. $0.52^\circ\text{C}$
C. $1.04^\circ\text{C}$
D. $0.026^\circ\text{C}$
Solution: $\Delta T_b = K_b \times m = 0.52 \times 0.1 = 0.052\text{ K}$.
Q3 — easy
A buffer solution contains $0.1\text{ M}$ acetic acid and $0.1\text{ M}$ sodium acetate. Given $pK_a$ of $\text{CH}_3\text{COOH} = 4.74$, the pH of the resulting buffer solution is:
A. 3.74
B. 4.74  ✓ Correct
C. 5.74
D. 7.00
Solution: Henderson-Hasselbalch: $\text{pH} = pK_a + \log([\text{salt}]/[\text{acid}]) = 4.74 + \log(1) = 4.74$.
Q4 — easy
The SI unit of the rate constant ($k$) for a second-order chemical reaction is:
A. $\text{s}^{-1}$
B. $\text{mol}\cdot\text{L}^{-1}\cdot\text{s}^{-1}$
C. $\text{L}\cdot\text{mol}^{-1}\cdot\text{s}^{-1}$  ✓ Correct
D. $\text{L}^2\cdot\text{mol}^{-2}\cdot\text{s}^{-1}$
Solution: For second order: $k = \text{Rate}/[A]^2$, giving units $\text{L}\cdot\text{mol}^{-1}\cdot\text{s}^{-1}$.
Q5 — easy
The steady decrease in ionic radii across the lanthanoid series ($\text{La}^{3+}$ to $\text{Lu}^{3+}$) is caused by:
A. Imperfect shielding of $4f$ electrons  ✓ Correct
B. Strong shielding by $5d$ electrons
C. Expansion of $6s$ orbital
D. Decrease in nuclear charge
Solution: Lanthanoid contraction: poor shielding by $4f$ electrons causes increasing effective nuclear charge.
Q6 — easy
An alkyl halide reacts with alcoholic potassium hydroxide ($\text{alc. KOH}$) to form an alkene via:
A. $\beta$-elimination (E2 mechanism)  ✓ Correct
B. Nucleophilic substitution ($\text{S}_\text{N}2$)
C. $\alpha$-elimination
D. $\text{S}_\text{N}1$ substitution
Solution: Alcoholic KOH is a strong base that abstracts a $\beta$-hydrogen via an E2 mechanism to generate an alkene.
Q7 — easy
The decreasing order of reactivity of alkyl halides towards bimolecular nucleophilic substitution ($\text{S}_\text{N}2$) is:
A. $1^\circ > 2^\circ > 3^\circ$  ✓ Correct
B. $3^\circ > 2^\circ > 1^\circ$
C. $2^\circ > 1^\circ > 3^\circ$
D. $1^\circ > 3^\circ > 2^\circ$
Solution: Steric hindrance at transition state: $\text{S}_\text{N}2$ reactivity is $1^\circ > 2^\circ > 3^\circ$.
Q8 — easy
Heating sodium phenoxide with carbon dioxide gas at $400\text{ K}$ under $4$--$7\text{ atm}$ pressure followed by acidification yields salicylic acid. This reaction is:
A. Reimer-Tiemann reaction
B. Kolbe-Schmitt reaction  ✓ Correct
C. Fries rearrangement
D. Williamson synthesis
Solution: Kolbe-Schmitt reaction converts sodium phenoxide to sodium salicylate via electrophilic carboxylation with $\text{CO}_2$.
Q9 — easy
Benzaldehyde on treatment with concentrated $50\%$ aqueous sodium hydroxide yields benzyl alcohol and sodium benzoate. This reaction is known as:
A. Aldol condensation
B. Cannizzaro reaction  ✓ Correct
C. Perkin reaction
D. Benzoin condensation
Solution: Benzaldehyde lacks an $\alpha$-hydrogen and undergoes Cannizzaro disproportionation in concentrated alkali.
Q10 — easy
Reduction of cyclohexanone with zinc amalgam ($\text{Zn-Hg}$) and concentrated $\text{HCl}$ to cyclohexane is known as:
A. Wolff-Kishner reduction
B. Clemmensen reduction  ✓ Correct
C. Rosenmund reduction
D. Stephen reduction
Solution: Clemmensen reduction uses $\text{Zn-Hg}/\text{HCl}$ to deoxygenate carbonyl groups.
Q11 — easy
The reaction of an aliphatic carboxylic acid with chlorine gas in the presence of red phosphorus to give an $\alpha$-chloro acid is:
A. Etard reaction
B. Hell-Volhard-Zelinsky (HVZ) reaction  ✓ Correct
C. Gattermann-Koch reaction
D. Hunsdiecker reaction
Solution: HVZ reaction halogenates aliphatic carboxylic acids at the $\alpha$-position using $\text{X}_2$/red P.
Q12 — easy
Which of the following carbohydrates is a non-reducing sugar?
A. D-Glucose
B. D-Fructose
C. Maltose
D. Sucrose  ✓ Correct
Solution: Sucrose has a glycosidic linkage between both anomeric carbons (C1 of glucose, C2 of fructose), locking both reducing centres.
Q13 — easy
The helical structure of a protein is maintained and stabilized primarily by:
A. Disulfide bridges
B. Hydrogen bonding  ✓ Correct
C. Peptide bonds
D. Ionic interactions
Solution: The $\alpha$-helix is stabilized by intramolecular hydrogen bonds between C=O and N-H groups.
Q14 — easy
Which nitrogenous base is present exclusively in RNA but absent in DNA?
A. Thymine
B. Uracil  ✓ Correct
C. Cytosine
D. Adenine
Solution: Uracil replaces thymine in RNA.
Q15 — easy
Nylon-6,6 is a synthetic polymer prepared by the polycondensation of:
A. Caprolactam
B. Hexamethylenediamine and adipic acid  ✓ Correct
C. Terephthalic acid and ethylene glycol
D. Phenol and formaldehyde
Solution: Nylon-6,6 = condensation of hexamethylenediamine + adipic acid.
Q16 — easy
Bakelite is formed through the cross-linking polymerisation of:
A. Phenol and formaldehyde  ✓ Correct
B. Melamine and formaldehyde
C. Urea and formaldehyde
D. Styrene and 1,3-butadiene
Solution: Bakelite is a cross-linked thermosetting resin from phenol + formaldehyde.
Q17 — easy
Natural rubber is chemically classified as a linear polymer of:
A. Chloroprene
B. cis-1,4-polyisoprene  ✓ Correct
C. trans-1,4-polyisoprene
D. Acrylonitrile
Solution: Natural rubber is cis-1,4-polyisoprene from isoprene monomer.
Q18 — easy
Which of the following is an example of a biodegradable polyester polymer?
A. Buna-N
B. PHBV  ✓ Correct
C. Nylon-6
D. Teflon
Solution: PHBV (poly-$\beta$-hydroxybutyrate-co-$\beta$-hydroxyvalerate) is a biodegradable copolymer.
Q19 — easy
According to the principles of green chemistry, atom economy (%) is maximized when:
A. All atoms of reactants are converted into desired products  ✓ Correct
B. Excess volatile solvent is used
C. Toxic heavy metal oxidants are consumed
D. A stoichiometric waste salt is formed
Solution: Maximum atom economy = 100% when all reactant atoms end up in the desired product.
Q20 — easy
The number of moles of water molecules present in $180\text{ g}$ of pure water is:
A. 1 mole
B. 5 moles
C. 10 moles  ✓ Correct
D. 18 moles
Solution: $n = w/M = 180/18 = 10\text{ moles}$.
Q21 — easy
The maximum number of electrons that can be accommodated in a subshell with azimuthal quantum number $l = 2$ is:
A. 2
B. 6
C. 10  ✓ Correct
D. 14
Solution: For $l = 2$ ($d$-subshell): orbitals $= 2l + 1 = 5$. Max electrons $= 2(2l+1) = 10$.
Q22 — easy
The oxidation number of chromium in potassium dichromate ($\text{K}_2\text{Cr}_2\text{O}_7$) is:
A. +3
B. +6  ✓ Correct
C. +5
D. +7
Solution: $2(+1) + 2x + 7(-2) = 0 \implies 2x = 12 \implies x = +6$.
Q23 — easy
According to Graham's law, the ratio of the rates of diffusion of methane ($\text{CH}_4$, $M = 16$) and sulfur dioxide ($\text{SO}_2$, $M = 64$) under identical conditions is:
A. 1 : 2
B. 2 : 1  ✓ Correct
C. 1 : 4
D. 4 : 1
Solution: $r_1/r_2 = \sqrt{M_2/M_1} = \sqrt{64/16} = 2:1$.
Q24 — hard
Which of the following complexes is diamagnetic and forms a low-spin inner-orbital complex?
A. $[\text{CoF}_6]^{3-}$
B. $[\text{FeF}_6]^{3-}$
C. $[\text{Co}(\text{NH}_3)_6]^{3+}$  ✓ Correct
D. $[\text{NiCl}_4]^{2-}$
Solution: $\text{NH}_3$ is a strong-field ligand with $\text{Co}^{3+}$ ($d^6$), causing complete pairing ($t_{2g}^6 e_g^0$). Diamagnetic inner-orbital complex.
Q25 — hard
According to IUPAC nomenclature, the coordination complex $[\text{Pt}(\text{NH}_3)_2\text{Cl}(\text{NO}_2)]$ is named as:
A. Diamminechloridonitrito-N-platinum(II)  ✓ Correct
B. Diamminechloronitroplatinum(IV)
C. Diamminedichloroplatinum(II)
D. Diamminenitritochloroplatinate(II)
Solution: Ligands alphabetically: diammine, chlorido, nitrito-$\kappa$N. Metal: platinum(II).
Q26 — medium
The packing efficiency of a face-centred cubic (fcc) unit cell is approximately:
A. 52.4%
B. 68.0%
C. 74.0%  ✓ Correct
D. 78.5%
Solution: In fcc, packing efficiency $= \frac{\pi}{3\sqrt{2}} \times 100\% \approx 74.0\%$.
Q27 — medium
The Henry's law constant ($K_H$) for a gas in water at $298\text{ K}$ is $1.6 \times 10^{-5}\text{ mol}\cdot\text{L}^{-1}\cdot\text{bar}^{-1}$. If the partial pressure of the gas above the solution is $2.5\text{ bar}$, its solubility is:
A. $4.0 \times 10^{-5}\text{ M}$  ✓ Correct
B. $6.4 \times 10^{-5}\text{ M}$
C. $4.0 \times 10^{-4}\text{ M}$
D. $6.4 \times 10^{-6}\text{ M}$
Solution: $S = K_H \times P = (1.6 \times 10^{-5})(2.5) = 4.0 \times 10^{-5}\text{ M}$.
Q28 — medium
The osmotic pressure of a $0.02\text{ M}$ solution of an electrolyte $\text{AB}_2$ ($i = 2.6$) at $300\text{ K}$ is ($R = 0.0821\text{ L}\cdot\text{atm}\cdot\text{mol}^{-1}\cdot\text{K}^{-1}$):
A. $0.492\text{ atm}$
B. $1.281\text{ atm}$  ✓ Correct
C. $0.640\text{ atm}$
D. $2.562\text{ atm}$
Solution: $\Pi = iCRT = 2.6 \times 0.02 \times 0.0821 \times 300 \approx 1.281\text{ atm}$.
Q29 — medium
The solubility product ($K_{sp}$) of a sparingly soluble salt $\text{Ag}_2\text{CrO}_4$ in terms of its molar solubility $S$ is expressed as:
A. $K_{sp} = S^2$
B. $K_{sp} = 4S^3$  ✓ Correct
C. $K_{sp} = 27S^4$
D. $K_{sp} = 2S^2$
Solution: $\text{Ag}_2\text{CrO}_4 \rightleftharpoons 2\text{Ag}^+ + \text{CrO}_4^{2-}$. $[\text{Ag}^+] = 2S$, $[\text{CrO}_4^{2-}] = S$. $K_{sp} = (2S)^2(S) = 4S^3$.
Q30 — medium
For the isothermal and reversible expansion of 2 moles of an ideal gas from $10\text{ L}$ to $100\text{ L}$ at $300\text{ K}$, the work done is ($R = 8.314\text{ J}\cdot\text{K}^{-1}\cdot\text{mol}^{-1}$, $\ln 10 = 2.303$):
A. $-11.49\text{ kJ}$  ✓ Correct
B. $-5.74\text{ kJ}$
C. $+11.49\text{ kJ}$
D. $-2.87\text{ kJ}$
Solution: $W = -2.303 nRT \log(V_2/V_1) = -2.303 \times 2 \times 8.314 \times 300 \times 1 = -11489\text{ J} \approx -11.49\text{ kJ}$.