Kinematics of Circular Motion — MH-CET Physics MCQs with Solutions
Free MH-CET Physics Kinematics of Circular Motion MCQs with step-by-step solutions (30 questions). Part of Circular Motion. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Kinematics of Circular Motion · easy · theory
The SI unit of angular displacement is the:
A. Revolution
B. Metre
C. Degree
D. Radian ✓ Correct
Solution: Angular displacement is measured in radians (rad) in SI units; 1 revolution = 2π rad.
Q2 — Kinematics of Circular Motion · easy · theory
Angular velocity (ω) is defined as the rate of change of angular displacement, and its SI unit is:
A. rad/s²
B. rev/min
C. m/s
D. rad/s ✓ Correct
Solution: ω = dθ/dt, so its SI unit is radian per second (rad/s).
Q3 — Kinematics of Circular Motion · easy · theory
The linear (tangential) speed v of a particle in circular motion of radius r is related to its angular speed ω by:
A. v = ω/r
B. v = r/ω
C. v = ωr ✓ Correct
D. v = ω²r
Solution: The linear speed is v = ωr.
Q4 — Kinematics of Circular Motion · medium · theory
The direction of the angular velocity vector of a particle in circular motion is:
A. Along the axis of rotation (given by the right-hand rule) ✓ Correct
B. Along the tangent to the circle
C. Directed towards the centre
D. Directed away from the centre
Solution: Angular velocity is an axial vector directed along the axis of rotation, its sense given by the right-hand rule.
Q5 — Kinematics of Circular Motion · easy · theory
In uniform circular motion (UCM):
A. Both speed and velocity are constant
B. The speed changes but the velocity is constant
C. The speed is constant but the velocity changes continuously ✓ Correct
D. Both speed and velocity change
Solution: In UCM the magnitude of velocity (speed) is constant, but its direction changes continuously, so velocity is not constant.
Q6 — Kinematics of Circular Motion · easy · theory
The centripetal acceleration of a particle in circular motion is always directed:
A. Along the tangent
B. Away from the centre
C. Towards the centre of the circle ✓ Correct
D. Along the axis of rotation
Solution: Centripetal acceleration points radially inward, towards the centre of the circular path.
Q7 — Kinematics of Circular Motion · medium · theory
The tangential acceleration of a particle moving in a circle:
A. Arises only when the angular speed changes, and equals αr ✓ Correct
B. Is always zero
C. Is present even in uniform circular motion
D. Is always directed towards the centre
Solution: Tangential acceleration a_t = αr appears only when the speed (angular speed) changes; in UCM α = 0 so a_t = 0.
Q8 — Kinematics of Circular Motion · easy · theory
In uniform circular motion, the angular acceleration of the particle is:
A. Constant and non-zero
B. Equal to ω²r
C. Directed towards the centre
D. Zero ✓ Correct
Solution: Uniform circular motion means constant angular speed, so angular acceleration α = 0.
Q9 — Kinematics of Circular Motion · medium · theory
When a particle moves in a circle with increasing speed, the angle between its centripetal and tangential accelerations is:
A. 45°
B. 90° ✓ Correct
C. 0°
D. 180°
Solution: Centripetal acceleration is radial (towards centre) and tangential acceleration is along the tangent; these are perpendicular, so the angle is 90°.
Q10 — Kinematics of Circular Motion · medium · theory
For a particle moving in a circle with both centripetal (a_c) and tangential (a_t) accelerations, the magnitude of the total (net) acceleration is:
A. $a_c + a_t$
B. $\sqrt{a_c^2 - a_t^2}$
C. $a_c \cdot a_t$
D. $\sqrt{a_c^2 + a_t^2}$ ✓ Correct
Solution: Since a_c and a_t are perpendicular, the net acceleration is a = √(a_c² + a_t²).
Q11 — Kinematics of Circular Motion · easy · theory
The number of radians in one complete revolution is:
A. π/2
B. π
C. 4π
D. 2π ✓ Correct
Solution: One complete revolution corresponds to an angular displacement of 2π radians (360°).
Q12 — Kinematics of Circular Motion · medium · theory
Which quantity remains constant for a particle in uniform circular motion?
A. Centripetal force direction
B. Kinetic energy ✓ Correct
C. Velocity
D. Linear momentum
Solution: Speed is constant in UCM, so kinetic energy (½mv²) is constant; velocity, momentum and the direction of the centripetal force all change.
Q13 — Kinematics of Circular Motion · easy · numerical
A wheel rotates at 300 rpm. Its angular velocity in rad/s is (take π = 3.14):
A. 3.14 rad/s
B. 18.8 rad/s
C. 31.4 rad/s ✓ Correct
D. 5 rad/s
Solution: ω = 2πN/60 = 2π × 300/60 = 10π = 31.4 rad/s.
Q14 — Kinematics of Circular Motion · easy · numerical
The angular velocity corresponding to 60 rpm is:
A. 2π rad/s ✓ Correct
B. π rad/s
C. 60 rad/s
D. 4π rad/s
Solution: ω = 2πN/60 = 2π × 60/60 = 2π rad/s.
Q15 — Kinematics of Circular Motion · easy · numerical
A particle moves in a circle of radius 0.5 m with an angular velocity of 2 rad/s. Its linear speed is:
A. 4 m/s
B. 2.5 m/s
C. 0.25 m/s
D. 1 m/s ✓ Correct
Solution: v = ωr = 2 × 0.5 = 1 m/s.
Q16 — Kinematics of Circular Motion · easy · numerical
A car moves on a circular track of radius 5 m at a speed of 10 m/s. Its centripetal acceleration is:
A. 2 m/s²
B. 10 m/s²
C. 20 m/s² ✓ Correct
D. 50 m/s²
Solution: a_c = v²/r = 10²/5 = 100/5 = 20 m/s².
Q17 — Kinematics of Circular Motion · easy · numerical
A body moves in a circle of radius 2 m with angular velocity 4 rad/s. Its centripetal acceleration is:
A. 32 m/s² ✓ Correct
B. 8 m/s²
C. 64 m/s²
D. 16 m/s²
Solution: a_c = ω²r = 4² × 2 = 16 × 2 = 32 m/s².
Q18 — Kinematics of Circular Motion · easy · numerical
The period of revolution of a particle whose angular velocity is π rad/s is:
A. 1 s
B. 2 s ✓ Correct
C. π s
D. 0.5 s
Solution: T = 2π/ω = 2π/π = 2 s.
Q19 — Kinematics of Circular Motion · medium · numerical
A particle has an angular velocity of 10π rad/s. Its frequency of revolution is:
A. 5 Hz ✓ Correct
B. 20 Hz
C. 2.5 Hz
D. 10 Hz
Solution: n = ω/2π = 10π/2π = 5 Hz.
Q20 — Kinematics of Circular Motion · easy · numerical
A wheel starting from rest attains an angular velocity of 100 rad/s in 5 s. Its angular acceleration is:
A. 20 rad/s² ✓ Correct
B. 500 rad/s²
C. 10 rad/s²
D. 25 rad/s²
Solution: α = (ω − ω₀)/t = (100 − 0)/5 = 20 rad/s².
Q21 — Kinematics of Circular Motion · easy · numerical
A rotating body has an initial angular velocity of 10 rad/s and an angular acceleration of 2 rad/s². Its angular velocity after 5 s is:
A. 12 rad/s
B. 30 rad/s
C. 15 rad/s
D. 20 rad/s ✓ Correct
Solution: ω = ω₀ + αt = 10 + 2 × 5 = 20 rad/s.
Q22 — Kinematics of Circular Motion · medium · numerical
A wheel starts from rest with an angular acceleration of 4 rad/s². The angular displacement in 3 s is:
A. 18 rad ✓ Correct
B. 36 rad
C. 9 rad
D. 12 rad
Solution: θ = ω₀t + ½αt² = 0 + ½ × 4 × 3² = ½ × 4 × 9 = 18 rad.
Q23 — Kinematics of Circular Motion · medium · numerical
A wheel starting from rest turns through 25 rad with an angular acceleration of 2 rad/s². Its final angular velocity is:
A. 10 rad/s ✓ Correct
B. 50 rad/s
C. 5 rad/s
D. 100 rad/s
Solution: ω² = ω₀² + 2αθ = 0 + 2 × 2 × 25 = 100 ⇒ ω = 10 rad/s.
Q24 — Kinematics of Circular Motion · easy · numerical
A particle moving in a circle of radius 2 m has an angular acceleration of 5 rad/s². Its tangential acceleration is:
A. 10 m/s² ✓ Correct
B. 2.5 m/s²
C. 20 m/s²
D. 7 m/s²
Solution: a_t = αr = 5 × 2 = 10 m/s².
Q25 — Kinematics of Circular Motion · medium · numerical
A particle in circular motion has a centripetal acceleration of 6 m/s² and a tangential acceleration of 8 m/s². The magnitude of its total acceleration is:
A. 48 m/s²
B. 10 m/s² ✓ Correct
C. 14 m/s²
D. 2 m/s²
Solution: a = √(a_c² + a_t²) = √(6² + 8²) = √(36 + 64) = √100 = 10 m/s².
Q26 — Kinematics of Circular Motion · easy · numerical
A disc rotates at 5 revolutions per second. Its angular velocity is (π = 3.14):
A. 5 rad/s
B. 15.7 rad/s
C. 10 rad/s
D. 31.4 rad/s ✓ Correct
Solution: ω = 2πn = 2π × 5 = 10π = 31.4 rad/s.
Q27 — Kinematics of Circular Motion · medium · numerical
The angular velocity of the second hand of a clock is approximately:
A. 1.0 rad/s
B. 0.105 rad/s ✓ Correct
C. 6.28 rad/s
D. 0.017 rad/s
Solution: The second hand completes one revolution (2π rad) in 60 s: ω = 2π/60 = π/30 ≈ 0.105 rad/s.
Q28 — Kinematics of Circular Motion · medium · numerical
A particle moves in a circle of radius 2 m. At an instant its speed is 4 m/s and its tangential acceleration is 3 m/s². Its total acceleration is:
A. 3 m/s²
B. 5 m/s²
C. ≈ 8.5 m/s² ✓ Correct
D. 11 m/s²
Solution: a_c = v²/r = 16/2 = 8 m/s². a = √(a_c² + a_t²) = √(8² + 3²) = √73 ≈ 8.5 m/s².
Q29 — Kinematics of Circular Motion · medium · numerical
If the speed of a particle in uniform circular motion is doubled while the radius is kept the same, its centripetal acceleration becomes:
A. 2 times
B. Unchanged
C. Half
D. 4 times ✓ Correct
Solution: a_c = v²/r ∝ v². Doubling v makes a_c increase by 2² = 4 times.
Q30 — Kinematics of Circular Motion · medium · numerical
A particle completes 300 revolutions per minute on a circle of radius 0.2 m. Its linear speed is (π = 3.14):
A. ≈ 3.14 m/s
B. ≈ 6.28 m/s ✓ Correct
C. ≈ 1.0 m/s
D. ≈ 12.6 m/s
Solution: n = 300/60 = 5 rev/s. v = 2πnr = 2π × 5 × 0.2 = 2π ≈ 6.28 m/s.