Magnetic Flux & Faraday's Laws — MH-CET Physics MCQs with Solutions
Free MH-CET Physics Magnetic Flux & Faraday's Laws MCQs with step-by-step solutions (21 questions). Part of Electromagnetic Induction. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Magnetic Flux & Faraday's Laws · easy · theory
The magnetic flux through a plane surface of area $A$ in a uniform field $B$, the normal making angle $\theta$ with the field, is:
A. $BA\sin\theta$
B. $\dfrac{BA}{\cos\theta}$
C. $BA\cos\theta$ ✓ Correct
D. $BA\tan\theta$
Solution: Flux is the scalar product $\vec{B}\cdot\vec{A}$, greatest when the surface is perpendicular to the field.
Q2 — Magnetic Flux & Faraday's Laws · easy · theory
Faraday's first law of electromagnetic induction states that:
A. An EMF is induced in a circuit whenever the magnetic flux linked with it changes ✓ Correct
B. The induced EMF is proportional to the flux itself
C. The induced current always opposes the applied field
D. Magnetic flux is always conserved
Solution: It is the change of flux, not its magnitude, that matters; a steady flux however large induces nothing.
Q3 — Magnetic Flux & Faraday's Laws · easy · theory
Faraday's second law gives the magnitude of the induced EMF in a coil of $N$ turns as:
A. $e = -\dfrac{N}{\Phi}\dfrac{dt}{d\Phi}$
B. $e = -N\dfrac{d\Phi}{dt}$ ✓ Correct
C. $e = -\dfrac{\Phi}{Nt}$
D. $e = -N\Phi t$
Solution: The minus sign expresses Lenz's law: the induced EMF opposes the change producing it.
Q4 — Magnetic Flux & Faraday's Laws · medium · theory
The induced EMF in a circuit depends on:
A. The resistance of the circuit
B. The magnitude of the magnetic flux
C. The total time for which the field acts
D. The rate of change of magnetic flux ✓ Correct
Solution: A large but constant flux induces no EMF, while a small flux changing rapidly induces a large one.
Q5 — Magnetic Flux & Faraday's Laws · hard · theory
The dimensional formula of magnetic flux is:
A. $[M^1L^1T^{-2}A^{-1}]$
B. $[M^1L^2T^{-2}A^{-1}]$ ✓ Correct
C. $[M^1L^2T^{-1}A^{-2}]$
D. $[M^0L^2T^{-2}A^{-1}]$
Solution: $\Phi = BA$, and $B = \dfrac{F}{IL}$, giving $\dfrac{[M^1L^1T^{-2}]}{[A][L]}[L^2] = [M^1L^2T^{-2}A^{-1}]$.
Q6 — Magnetic Flux & Faraday's Laws · medium · theory
The magnetic flux linked with a coil can be changed by:
A. Changing the field, the area, or the orientation of the coil ✓ Correct
B. Changing the resistance of the coil
C. Changing only the magnetic field
D. Changing only the area of the coil
Solution: Since $\Phi = BA\cos\theta$, altering any of the three quantities changes the flux and induces an EMF.
Q7 — Magnetic Flux & Faraday's Laws · medium · theory
When the flux through an open (unclosed) coil changes:
A. Both EMF and current appear
B. Neither EMF nor current appears
C. A current flows but no EMF appears
D. An EMF is induced but no current flows ✓ Correct
Solution: The EMF exists whenever the flux changes; a complete conducting path is needed only for the current.
Q8 — Magnetic Flux & Faraday's Laws · easy · theory
One weber is equivalent to:
A. $1\text{ A}\cdot\text{m}^2$
B. $1\text{ T}/\text{m}^2$
C. $1\text{ T}\cdot\text{m}^2$ ✓ Correct
D. $1\text{ V}/\text{s}$
Solution: It is also one volt second, since an EMF of one volt corresponds to flux changing at one weber per second.
Q9 — Magnetic Flux & Faraday's Laws · easy · numerical
The flux linked with a coil changes from $0.8\text{ Wb}$ to $0.2\text{ Wb}$ in $0.1\text{ s}$. The induced EMF is:
A. $0.6\text{ V}$
B. $6\text{ V}$ ✓ Correct
C. $10\text{ V}$
D. $60\text{ V}$
Solution: $|e| = \left|\dfrac{\Delta\Phi}{\Delta t}\right| = \dfrac{0.8 - 0.2}{0.1} = 6\text{ V}$.
Q10 — Magnetic Flux & Faraday's Laws · easy · numerical
A coil of $100$ turns has flux changing at $0.02\text{ Wb}/\text{s}$. The induced EMF is:
A. $0.2\text{ V}$
B. $2\text{ V}$ ✓ Correct
C. $5000\text{ V}$
D. $20\text{ V}$
Solution: $e = N\dfrac{d\Phi}{dt} = 100 \times 0.02 = 2\text{ V}$.
Q11 — Magnetic Flux & Faraday's Laws · easy · numerical
A coil of area $0.02\text{ m}^2$ lies perpendicular to a field of $0.5\text{ T}$. The flux through it is:
A. $0.1\text{ Wb}$
B. $0.04\text{ Wb}$
C. $0.01\text{ Wb}$ ✓ Correct
D. $25\text{ Wb}$
Solution: $\Phi = BA\cos 0^\circ = 0.5 \times 0.02 = 0.01\text{ Wb}$.
Q12 — Magnetic Flux & Faraday's Laws · medium · numerical
A coil of area $0.05\text{ m}^2$ has its normal at $60^\circ$ to a field of $0.4\text{ T}$. The flux through it is:
A. $0.01\text{ Wb}$ ✓ Correct
B. $0.017\text{ Wb}$
C. $0.02\text{ Wb}$
D. $0.005\text{ Wb}$
Solution: $\Phi = BA\cos 60^\circ = 0.4 \times 0.05 \times 0.5 = 0.01\text{ Wb}$.
Q13 — Magnetic Flux & Faraday's Laws · medium · numerical
A coil of $50$ turns experiences a flux change of $0.5\text{ Wb}$ in $0.2\text{ s}$. The induced EMF is:
A. $250\text{ V}$
B. $125\text{ V}$ ✓ Correct
C. $25\text{ V}$
D. $12.5\text{ V}$
Solution: $e = N\dfrac{\Delta\Phi}{\Delta t} = 50 \times \dfrac{0.5}{0.2} = 125\text{ V}$.
Q14 — Magnetic Flux & Faraday's Laws · hard · numerical
A coil of $200$ turns and area $0.01\text{ m}^2$ has the field through it changed from $0.1\text{ T}$ to $0.5\text{ T}$ in $0.2\text{ s}$. The induced EMF is:
A. $8\text{ V}$
B. $2\text{ V}$
C. $0.4\text{ V}$
D. $4\text{ V}$ ✓ Correct
Solution: $e = NA\dfrac{\Delta B}{\Delta t} = 200 \times 0.01 \times \dfrac{0.4}{0.2} = 4\text{ V}$.
Q15 — Magnetic Flux & Faraday's Laws · hard · numerical
A coil of $100$ turns and resistance $10\,\Omega$ has its flux changed by $0.01\text{ Wb}$. The charge that flows is:
A. $1\text{ C}$
B. $10\text{ C}$
C. $0.1\text{ C}$ ✓ Correct
D. $0.01\text{ C}$
Solution: $q = \dfrac{N\Delta\Phi}{R} = \dfrac{100 \times 0.01}{10} = 0.1\text{ C}$, independent of how fast the change occurs.
Q16 — Magnetic Flux & Faraday's Laws · medium · numerical
The flux through a coil varies as $\Phi = 5t^2\text{ weber}$. The induced EMF at $t = 2\text{ s}$ is:
A. $5\text{ V}$
B. $40\text{ V}$
C. $10\text{ V}$
D. $20\text{ V}$ ✓ Correct
Solution: $e = \dfrac{d\Phi}{dt} = 10t$. At $t = 2\text{ s}$, $e = 20\text{ V}$.
Q17 — Magnetic Flux & Faraday's Laws · medium · numerical
The flux through a coil varies as $\Phi = (3t + 4)\text{ weber}$. The induced EMF is:
A. $7\text{ V}$
B. $4\text{ V}$, constant in time
C. $3\text{ V}$, constant in time ✓ Correct
D. Zero
Solution: $e = \dfrac{d\Phi}{dt} = 3\text{ V}$; the constant term contributes nothing.
Q18 — Magnetic Flux & Faraday's Laws · hard · numerical
A coil of area $0.1\text{ m}^2$ in a field of $0.2\text{ T}$ is rotated from a position perpendicular to the field to one parallel to it in $0.5\text{ s}$. The average induced EMF is:
A. $0.1\text{ V}$
B. $0.4\text{ V}$
C. $0.04\text{ V}$ ✓ Correct
D. $0.02\text{ V}$
Solution: The flux falls from $0.02\text{ Wb}$ to zero, so $e = \dfrac{0.02}{0.5} = 0.04\text{ V}$.
Q19 — Magnetic Flux & Faraday's Laws · easy · numerical
A coil of area $0.04\text{ m}^2$ lies with its plane perpendicular to a field of $0.3\text{ T}$. The flux through it is:
A. $0.12\text{ Wb}$
B. $0.012\text{ Wb}$ ✓ Correct
C. $7.5\text{ Wb}$
D. $0.0012\text{ Wb}$
Solution: $\Phi = BA = 0.3 \times 0.04 = 0.012\text{ Wb}$.
Q20 — Magnetic Flux & Faraday's Laws · medium · numerical
A coil of $500$ turns has its flux changed by $0.004\text{ Wb}$ in $0.01\text{ s}$. The induced EMF is:
A. $20\text{ V}$
B. $200\text{ V}$ ✓ Correct
C. $2000\text{ V}$
D. $2\text{ V}$
Solution: $e = 500 \times \dfrac{0.004}{0.01} = 500 \times 0.4 = 200\text{ V}$.
Q21 — Magnetic Flux & Faraday's Laws · medium · numerical
A coil is held so that its normal makes $30^\circ$ with a field of $0.6\text{ T}$. If its area is $0.02\text{ m}^2$, the flux is approximately:
A. $0.024\text{ Wb}$
B. $0.0104\text{ Wb}$ ✓ Correct
C. $0.012\text{ Wb}$
D. $0.006\text{ Wb}$
Solution: $\Phi = BA\cos 30^\circ = 0.6 \times 0.02 \times 0.866 \approx 0.0104\text{ Wb}$.