Resolution of Vectors & Components — MH-CET Physics MCQs with Solutions
Free MH-CET Physics Resolution of Vectors & Components MCQs with step-by-step solutions (21 questions). Part of Mathematical Methods (Std 11). Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Resolution of Vectors & Components · easy · theory
Resolution of a vector means:
A. Adding it to another vector
B. Splitting it into components along chosen directions ✓ Correct
C. Reversing its direction
D. Finding its magnitude
Solution: It is the reverse process of vector addition.
Q2 — Resolution of Vectors & Components · easy · theory
The rectangular components of a vector $\vec{A}$ making an angle $\theta$ with the $x$-axis are:
A. $A\tan\theta$ and $A$
B. $A$ and $A\tan\theta$
C. $A\sin\theta$ and $A\cos\theta$
D. $A\cos\theta$ and $A\sin\theta$ ✓ Correct
Solution: The angle is measured from the $x$-axis, so the horizontal component carries the cosine.
Q3 — Resolution of Vectors & Components · easy · theory
The magnitude of a vector in terms of its rectangular components is:
A. $A_xA_y$
B. $A_x + A_y$
C. $\sqrt{A_x^2 + A_y^2}$ ✓ Correct
D. $\sqrt{A_x^2 - A_y^2}$
Solution: The components form the perpendicular sides of a right triangle whose hypotenuse is the vector.
Q4 — Resolution of Vectors & Components · medium · theory
The direction of a vector in terms of its components is given by:
A. $\tan\theta = \dfrac{A_x}{A_y}$
B. $\sin\theta = \dfrac{A_y}{A_x}$
C. $\tan\theta = \dfrac{A_y}{A_x}$ ✓ Correct
D. $\cos\theta = \dfrac{A_y}{A_x}$
Solution: The angle is measured from the positive $x$-axis.
Q5 — Resolution of Vectors & Components · medium · theory
In three dimensions, a vector can be resolved into:
A. A single component
B. Two components only
C. Three mutually perpendicular components ✓ Correct
D. Four components
Solution: These are written $A_x\hat{i} + A_y\hat{j} + A_z\hat{k}$.
Q6 — Resolution of Vectors & Components · hard · theory
The direction cosines of a vector are the cosines of the angles it makes with the:
A. Horizontal plane only
B. Three coordinate axes ✓ Correct
C. Two coordinate axes only
D. Resultant vector
Solution: They satisfy $\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1$.
Q7 — Resolution of Vectors & Components · medium · theory
A vector can be resolved into components along:
A. Only the coordinate axes
B. Only one direction
C. Any two non-parallel directions in its plane ✓ Correct
D. Only mutually perpendicular directions
Solution: Rectangular resolution is merely the most convenient special case.
Q8 — Resolution of Vectors & Components · hard · theory
When a vector is resolved into two perpendicular components, the sum of the magnitudes of the components is:
A. Generally greater than the magnitude of the vector ✓ Correct
B. Always equal to the magnitude of the vector
C. Always zero
D. Always less than the magnitude of the vector
Solution: Components add as vectors, not as numbers: $3 + 4 = 7$ while the vector has magnitude $5$.
Q9 — Resolution of Vectors & Components · medium · numerical
A vector of magnitude $10$ makes $30^\circ$ with the $x$-axis. Its $x$ and $y$ components are approximately:
A. $10$ and $0$
B. $5$ and $8.66$
C. $7.07$ and $7.07$
D. $8.66$ and $5$ ✓ Correct
Solution: $A_x = 10\cos 30^\circ \approx 8.66$ and $A_y = 10\sin 30^\circ = 5$.
Q10 — Resolution of Vectors & Components · medium · numerical
A vector of magnitude $20$ makes $60^\circ$ with the $x$-axis. Its $x$ component is:
A. $20$
B. $14.14$
C. $17.32$
D. $10$ ✓ Correct
Solution: $A_x = 20\cos 60^\circ = 20 \times 0.5 = 10$.
Q11 — Resolution of Vectors & Components · medium · numerical
A vector of magnitude $100$ makes $45^\circ$ with the $x$-axis. Each of its components is approximately:
A. $100$
B. $86.6$
C. $50$
D. $70.7$ ✓ Correct
Solution: $100\cos 45^\circ = 100\sin 45^\circ \approx 70.7$.
Q12 — Resolution of Vectors & Components · hard · numerical
A vector has components $3$ and $4$ along the $x$ and $y$ axes. Its magnitude and direction are:
A. $7$ at $\tan^{-1}\left(\dfrac{3}{4}\right)$
B. $5$ at $\tan^{-1}\left(\dfrac{4}{3}\right)$ to the $x$-axis ✓ Correct
C. $12$ at $45^\circ$
D. $5$ at $\tan^{-1}\left(\dfrac{3}{4}\right)$
Solution: $A = \sqrt{9 + 16} = 5$ and $\tan\theta = \dfrac{A_y}{A_x} = \dfrac{4}{3}$, giving about $53.1^\circ$.
Q13 — Resolution of Vectors & Components · medium · numerical
A force of $50\text{ N}$ acts at $37^\circ$ to the horizontal. Its horizontal component is approximately ($\cos 37^\circ = 0.8$):
A. $30\text{ N}$
B. $40\text{ N}$ ✓ Correct
C. $50\text{ N}$
D. $25\text{ N}$
Solution: $F_x = 50 \times 0.8 = 40\text{ N}$.
Q14 — Resolution of Vectors & Components · medium · numerical
For the same force of $50\text{ N}$ at $37^\circ$, the vertical component is approximately ($\sin 37^\circ = 0.6$):
A. $40\text{ N}$
B. $50\text{ N}$
C. $25\text{ N}$
D. $30\text{ N}$ ✓ Correct
Solution: $F_y = 50 \times 0.6 = 30\text{ N}$.
Q15 — Resolution of Vectors & Components · medium · numerical
A projectile is launched at $20\text{ m/s}$ at $30^\circ$ to the horizontal. Its horizontal component of velocity is approximately:
A. $17.3\text{ m/s}$ ✓ Correct
B. $14.1\text{ m/s}$
C. $20\text{ m/s}$
D. $10\text{ m/s}$
Solution: $v_x = 20\cos 30^\circ \approx 17.3\text{ m/s}$.
Q16 — Resolution of Vectors & Components · medium · numerical
For the same projectile ($20\text{ m/s}$ at $30^\circ$), the vertical component of velocity is:
A. $10\text{ m/s}$ ✓ Correct
B. $17.3\text{ m/s}$
C. $20\text{ m/s}$
D. $5\text{ m/s}$
Solution: $v_y = 20\sin 30^\circ = 10\text{ m/s}$.
Q17 — Resolution of Vectors & Components · hard · numerical
A vector of magnitude $13$ has an $x$ component of $5$. Its $y$ component is:
A. $18$
B. $12$ ✓ Correct
C. $65$
D. $8$
Solution: $A_y = \sqrt{13^2 - 5^2} = \sqrt{144} = 12$.
Q18 — Resolution of Vectors & Components · hard · numerical
A block of weight $100\text{ N}$ rests on an incline of $30^\circ$. The component of its weight along the incline is:
A. $70.7\text{ N}$
B. $86.6\text{ N}$
C. $50\text{ N}$ ✓ Correct
D. $100\text{ N}$
Solution: The component along the surface is $W\sin\theta = 100 \times 0.5 = 50\text{ N}$.
Q19 — Resolution of Vectors & Components · hard · numerical
For the same block on the $30^\circ$ incline, the component of weight perpendicular to the surface is approximately:
A. $50\text{ N}$
B. $100\text{ N}$
C. $70.7\text{ N}$
D. $86.6\text{ N}$ ✓ Correct
Solution: The perpendicular component is $W\cos\theta = 100 \times 0.866 \approx 86.6\text{ N}$.
Q20 — Resolution of Vectors & Components · easy · numerical
A vector has equal $x$ and $y$ components. The angle it makes with the $x$-axis is:
A. $90^\circ$
B. $60^\circ$
C. $45^\circ$ ✓ Correct
D. $30^\circ$
Solution: $\tan\theta = \dfrac{A_y}{A_x} = 1$, so $\theta = 45^\circ$.
Q21 — Resolution of Vectors & Components · medium · numerical
A vector of magnitude $A$ makes $60^\circ$ with the $x$-axis. Its $x$ component is:
A. $\dfrac{A\sqrt{3}}{2}$
B. $\dfrac{A}{\sqrt{2}}$
C. $A$
D. $\dfrac{A}{2}$ ✓ Correct
Solution: $A_x = A\cos 60^\circ = \dfrac{A}{2}$.