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Motion in a Plane (Std 11) — MH-CET Physics MCQs with Solutions
Free MH-CET Physics Motion in a Plane (Std 11) MCQs with step-by-step solutions covering Displacement, Velocity & Acceleration, Equations of Motion, Relative Velocity, Projectile Motion — Basics, Projectile Motion — Range & Height, Uniform Circular Motion. Practise online on Prepizo — no login needed.
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Sample questions with solutions
Q1 — Displacement, Velocity & Acceleration · easy · theory
Distance and displacement differ in that displacement is:
A. A vector giving the shortest path from start to finish ✓ Correct
B. Always greater than the distance
C. Always equal to the distance
D. A scalar giving the total path length
Solution: Distance depends on the path taken; displacement depends only on the end points.
Q2 — Displacement, Velocity & Acceleration · easy · theory
Speed and velocity differ in that velocity:
A. Cannot be negative
B. Is a vector, so its direction matters ✓ Correct
C. Is a scalar, unlike speed
D. Is always greater than speed
Solution: A body may move at constant speed yet have changing velocity if its direction changes.
Q3 — Displacement, Velocity & Acceleration · easy · theory
Acceleration is defined as the:
A. Product of velocity and time
B. Rate of change of displacement with time
C. Rate of change of velocity with time ✓ Correct
D. Rate of change of speed with distance
Solution: Because velocity is a vector, a change of direction alone constitutes an acceleration.
Q4 — Displacement, Velocity & Acceleration · easy · theory
A body moving with uniform velocity has:
A. Zero acceleration ✓ Correct
B. Variable velocity
C. Constant non-zero acceleration
D. Increasing acceleration
Solution: Uniform velocity means both the magnitude and the direction are unchanging.
Q5 — Displacement, Velocity & Acceleration · easy · numerical
A body covers $100\text{ m}$ in $20\text{ s}$. Its average speed is:
A. $50\text{ m/s}$
B. $2000\text{ m/s}$
C. $5\text{ m/s}$ ✓ Correct
D. $0.2\text{ m/s}$
Solution: Average speed $= \dfrac{100}{20} = 5\text{ m/s}$.
Q6 — Displacement, Velocity & Acceleration · easy · numerical
A body accelerates uniformly from rest to $20\text{ m/s}$ in $4\text{ s}$. Its acceleration is:
A. $0.2\text{ m/s}^2$
B. $80\text{ m/s}^2$
C. $4\text{ m/s}^2$
D. $5\text{ m/s}^2$ ✓ Correct
Solution: $a = \dfrac{v - u}{t} = \dfrac{20 - 0}{4} = 5\text{ m/s}^2$.
Q7 — Displacement, Velocity & Acceleration · easy · numerical
A body undergoes a displacement of $5\text{ m}$ in $2\text{ s}$. Its average velocity is:
A. $0.4\text{ m/s}$
B. $5\text{ m/s}$
C. $2.5\text{ m/s}$ ✓ Correct
D. $10\text{ m/s}$
Solution: Average velocity $= \dfrac{5}{2} = 2.5\text{ m/s}$ in the direction of the displacement.
Q8 — Displacement, Velocity & Acceleration · easy · numerical
A speed of $72\text{ km/h}$ expressed in metre per second is:
A. $18\text{ m/s}$
B. $36\text{ m/s}$
C. $20\text{ m/s}$ ✓ Correct
D. $25\text{ m/s}$
Solution: $72 \times \dfrac{5}{18} = 20\text{ m/s}$.
Q9 — Displacement, Velocity & Acceleration · easy · numerical
A body speeds up uniformly from $5\text{ m/s}$ to $25\text{ m/s}$ in $4\text{ s}$. Its acceleration is:
A. $6.25\text{ m/s}^2$
B. $20\text{ m/s}^2$
C. $5\text{ m/s}^2$ ✓ Correct
D. $1.25\text{ m/s}^2$
Solution: $a = \dfrac{25 - 5}{4} = 5\text{ m/s}^2$.
Q10 — Displacement, Velocity & Acceleration · easy · numerical
A body moves at a steady $15\text{ m/s}$ for $10\text{ s}$. The distance covered is:
A. $1.5\text{ m}$
B. $150\text{ m}$ ✓ Correct
C. $75\text{ m}$
D. $25\text{ m}$
Solution: Distance $= vt = 15 \times 10 = 150\text{ m}$.
Q11 — Equations of Motion · easy · theory
The equation $v = u + at$ is valid only when the:
A. Velocity is uniform
B. Acceleration is uniform ✓ Correct
C. Body moves in a circle
D. Body starts from rest
Solution: All three kinematic equations assume a constant acceleration.
Q12 — Equations of Motion · easy · theory
The equation giving displacement in terms of time is:
A. $s = ut + at^2$
B. $s = \dfrac{1}{2}at$
C. $s = ut + \dfrac{1}{2}at^2$ ✓ Correct
D. $s = u + \dfrac{1}{2}at^2$
Solution: The first term is the displacement at constant velocity, the second the extra due to acceleration.
Q13 — Equations of Motion · easy · theory
The equation connecting velocity and displacement without time is:
A. $v^2 = u^2 + at$
B. $s = ut + \dfrac{1}{2}at^2$
C. $v = u + at$
D. $v^2 = u^2 + 2as$ ✓ Correct
Solution: It is obtained by eliminating $t$ between the other two equations.
Q14 — Equations of Motion · easy · theory
For a body in free fall near the Earth, the acceleration is:
A. Zero
B. Dependent on the mass of the body
C. Equal to $g$ and directed vertically downward ✓ Correct
D. Equal to $g$ and directed upward
Solution: In the absence of air resistance all bodies fall with the same acceleration.
Q15 — Equations of Motion · easy · numerical
A body moving at $10\text{ m/s}$ accelerates at $2\text{ m/s}^2$ for $3\text{ s}$. Its final velocity is:
A. $13\text{ m/s}$
B. $6\text{ m/s}$
C. $16\text{ m/s}$ ✓ Correct
D. $30\text{ m/s}$
Solution: $v = u + at = 10 + 2(3) = 16\text{ m/s}$.
Q16 — Equations of Motion · easy · numerical
A body is thrown vertically upward at $20\text{ m/s}$. The time it takes to reach the highest point is ($g = 10\text{ m/s}^2$):
A. $4\text{ s}$
B. $1\text{ s}$
C. $20\text{ s}$
D. $2\text{ s}$ ✓ Correct
Solution: $t = \dfrac{u}{g} = \dfrac{20}{10} = 2\text{ s}$.
Q17 — Equations of Motion · easy · theory
Two bodies of different masses are dropped from the same height in the absence of air resistance. They reach the ground:
A. The heavier one first
B. At times proportional to their masses
C. At the same time, since the acceleration is independent of mass ✓ Correct
D. The lighter one first
Solution: The equation $h = \dfrac{1}{2}gt^2$ contains no mass term.
Q18 — Relative Velocity · easy · theory
The relative velocity of body $A$ with respect to body $B$ is given by:
A. $\vec{v}_A - \vec{v}_B$ ✓ Correct
B. $\vec{v}_B - \vec{v}_A$
C. $\vec{v}_A\cdot\vec{v}_B$
D. $\vec{v}_A + \vec{v}_B$
Solution: It is the velocity $A$ appears to have to an observer moving with $B$.
Q19 — Relative Velocity · easy · theory
For two bodies moving in the same direction, the magnitude of their relative velocity is:
A. Always zero
B. The sum of their speeds
C. The difference of their speeds ✓ Correct
D. The product of their speeds
Solution: This is why a train alongside another moving at the same speed appears at rest.
Q20 — Relative Velocity · easy · theory
For two bodies moving in opposite directions, the magnitude of their relative velocity is:
A. The difference of their speeds
B. Zero
C. The product of their speeds
D. The sum of their speeds ✓ Correct
Solution: Their separation changes at the combined rate, which is why oncoming traffic seems to rush past.
Q21 — Relative Velocity · easy · numerical
Two cars move in the same direction at $60\text{ km/h}$ and $40\text{ km/h}$. Their relative speed is:
A. $100\text{ km/h}$
B. $20\text{ km/h}$ ✓ Correct
C. $50\text{ km/h}$
D. $2400\text{ km/h}$
Solution: Same direction means the speeds subtract: $60 - 40 = 20\text{ km/h}$.
Q22 — Relative Velocity · easy · numerical
Two cars move in opposite directions at $60\text{ km/h}$ and $40\text{ km/h}$. Their relative speed is:
A. $2400\text{ km/h}$
B. $100\text{ km/h}$ ✓ Correct
C. $50\text{ km/h}$
D. $20\text{ km/h}$
Solution: Opposite directions means the speeds add.
Q23 — Relative Velocity · easy · numerical
A man walks at $5\text{ m/s}$ and a bus moves in the same direction at $15\text{ m/s}$. The velocity of the bus relative to the man is:
A. $3\text{ m/s}$
B. $10\text{ m/s}$ ✓ Correct
C. $75\text{ m/s}$
D. $20\text{ m/s}$
Solution: $v_{bus} - v_{man} = 15 - 5 = 10\text{ m/s}$.
Q24 — Relative Velocity · easy · numerical
Two trains move towards each other at $30\text{ m/s}$ and $20\text{ m/s}$. Their relative speed is:
A. $600\text{ m/s}$
B. $10\text{ m/s}$
C. $50\text{ m/s}$ ✓ Correct
D. $25\text{ m/s}$
Solution: Approaching bodies have their speeds added.
Q25 — Relative Velocity · easy · numerical
Two bodies move with the same velocity in the same direction. The velocity of one relative to the other is:
A. Twice the velocity of either
B. Zero ✓ Correct
C. Perpendicular to their motion
D. Equal to the velocity of either
Solution: $\vec{v}_A - \vec{v}_B = 0$ when the two velocity vectors are identical.
Q26 — Projectile Motion — Basics · easy · theory
The path followed by a projectile in the absence of air resistance is:
A. A straight line
B. A circle
C. A hyperbola
D. A parabola ✓ Correct
Solution: Uniform horizontal motion combined with uniformly accelerated vertical motion gives a parabola.
Q27 — Projectile Motion — Basics · easy · theory
During projectile motion, the horizontal component of velocity:
A. Becomes zero at the top
B. Remains constant throughout ✓ Correct
C. Increases steadily
D. Decreases steadily
Solution: There is no horizontal force, so there is no horizontal acceleration.
Q28 — Projectile Motion — Basics · easy · theory
During projectile motion, the vertical component of velocity:
A. Remains constant
B. Increases steadily throughout
C. Changes uniformly under gravity ✓ Correct
D. Is always zero
Solution: It decreases on the way up, is zero at the top and increases on the way down.
Q29 — Projectile Motion — Basics · easy · theory
For a body projected horizontally from a height, the initial vertical velocity is:
A. Zero ✓ Correct
B. Maximum
C. Equal to $g$
D. Equal to the horizontal velocity
Solution: The body falls exactly as though dropped from rest, while moving horizontally at constant speed.
Q30 — Projectile Motion — Basics · easy · numerical
A projectile launched at angle $\theta$ with speed $u$ has a vertical component of initial velocity equal to:
A. $u\sin\theta$ ✓ Correct
B. $u$
C. $u\cos\theta$
D. $u\tan\theta$
Solution: The vertical component governs the height reached and the time of flight.