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Atomic Structure — NEET Chemistry MCQs with Solutions

Free NEET Chemistry Atomic Structure MCQs with step-by-step solutions covering Sub-atomic Particles, Atomic Models, Developments Leading to Bohr's Model, Bohr's Model for Hydrogen Atom, Towards the Quantum Mechanical Model, Quantum Mechanical Model of the Atom. Practise online on Prepizo — no login needed.

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Sample questions with solutions

Q1 — Sub-atomic Particles · easy · theory
The electron was discovered by:
A. James Chadwick
B. E. Rutherford
C. J. J. Thomson  ✓ Correct
D. R. A. Millikan
Solution: J. J. Thomson (1897) studied cathode rays and established the existence of the electron, also measuring its charge-to-mass ratio.
Q2 — Sub-atomic Particles · easy · theory
Cathode rays are a stream of:
A. Negatively charged particles (electrons)  ✓ Correct
B. Electromagnetic waves
C. Positively charged particles
D. Neutral particles
Solution: Cathode rays consist of electrons — negatively charged particles that travel from the cathode to the anode in a discharge tube.
Q3 — Sub-atomic Particles · easy · theory
The charge on a single electron is approximately:
A. $-1.6 \times 10^{-27}$ C
B. $-6.6 \times 10^{-34}$ C
C. $-9.1 \times 10^{-31}$ C
D. $-1.6 \times 10^{-19}$ C  ✓ Correct
Solution: The magnitude of the electron's charge is 1.6 × 10⁻¹⁹ C, determined by Millikan. 9.1 × 10⁻³¹ kg is its mass, not charge.
Q4 — Sub-atomic Particles · easy · theory
The charge-to-mass ratio (e/mₑ) of the electron has a value of about:
A. $1.6 \times 10^{-19}$ C/kg
B. $1.76 \times 10^{11}$ C/kg  ✓ Correct
C. $6.02 \times 10^{23}$ C/kg
D. $9.58 \times 10^{7}$ C/kg
Solution: Thomson measured e/mₑ = 1.76 × 10¹¹ C/kg for the electron. (9.58 × 10⁷ C/kg is the value for the proton.)
Q5 — Sub-atomic Particles · easy · theory
Millikan's oil drop experiment was designed to determine the:
A. Charge on the electron  ✓ Correct
B. Charge-to-mass ratio of the electron
C. Mass of the proton
D. Radius of the nucleus
Solution: Millikan's oil drop experiment measured the charge on the electron (1.6 × 10⁻¹⁹ C) and showed that charge is always an integral multiple of this value.
Q6 — Sub-atomic Particles · easy · theory
The charge-to-mass ratio (e/m) of the electron was first determined by:
A. E. Goldstein
B. R. A. Millikan
C. J. J. Thomson  ✓ Correct
D. J. Chadwick
Solution: Thomson determined e/m of the electron by studying the deflection of cathode rays in electric and magnetic fields.
Q7 — Sub-atomic Particles · easy · theory
The neutron was discovered by:
A. Ernest Rutherford
B. James Chadwick  ✓ Correct
C. J. J. Thomson
D. E. Goldstein
Solution: James Chadwick (1932) discovered the neutron by bombarding beryllium with α-particles, producing a neutral radiation.
Q8 — Sub-atomic Particles · easy · theory
Anode rays (canal rays), which led to the discovery of the proton, were first observed by:
A. J. J. Thomson
B. E. Goldstein  ✓ Correct
C. R. A. Millikan
D. Niels Bohr
Solution: E. Goldstein (1886) discovered canal rays (anode rays) using a perforated cathode; the lightest positive particle (from hydrogen) was later identified as the proton.
Q9 — Sub-atomic Particles · easy · theory
The charge present on a proton is:
A. $+3.2 \times 10^{-19}$ C
B. Zero
C. $+1.6 \times 10^{-19}$ C  ✓ Correct
D. $-1.6 \times 10^{-19}$ C
Solution: The proton carries a positive charge equal in magnitude to the electron's charge: +1.6 × 10⁻¹⁹ C.
Q10 — Sub-atomic Particles · easy · theory
In an electric field, cathode rays are deflected towards the:
A. Positive plate  ✓ Correct
B. Neither plate
C. Both plates equally
D. Negative plate
Solution: Being negatively charged, cathode ray electrons are attracted to and deflected towards the positive plate.
Q11 — Sub-atomic Particles · easy · theory
The particle that has a mass of about 1 atomic mass unit and a charge of +1 is the:
A. Neutron
B. Electron
C. Proton  ✓ Correct
D. Positron
Solution: The proton has mass ≈ 1 u and charge +1. The neutron also has mass ≈ 1 u but is neutral; the electron is far lighter.
Q12 — Sub-atomic Particles · easy · theory
The discovery of the proton is associated with the study of:
A. Cathode rays
B. Anode rays (canal rays)  ✓ Correct
C. X-rays
D. γ-rays
Solution: Positive (anode/canal) rays, produced from a perforated cathode, led to the identification of the proton as the lightest positive particle (from hydrogen).
Q13 — Sub-atomic Particles · easy · theory
Which statement about the neutron is correct?
A. It was discovered before the electron
B. It carries a charge of −1.6 × 10⁻¹⁹ C
C. It is lighter than an electron
D. It is electrically neutral with mass close to that of a proton  ✓ Correct
Solution: The neutron is neutral, has a mass just above the proton's, and was discovered (1932) long after the electron (1897).
Q14 — Atomic Models · easy · theory
Thomson's model of the atom is popularly known as the:
A. Quantum model
B. Planetary model
C. Plum pudding model  ✓ Correct
D. Nuclear model
Solution: Thomson pictured the atom as a sphere of positive charge with electrons embedded in it, like plums in a pudding (also called the watermelon model).
Q15 — Atomic Models · easy · theory
In Thomson's model, the electrons are:
A. Embedded in a sphere of uniform positive charge  ✓ Correct
B. Present outside the atom
C. Revolving around a central nucleus
D. Located only at the centre of the atom
Solution: Thomson proposed a uniform sphere of positive charge with the negatively charged electrons studded throughout it, keeping the atom neutral.
Q16 — Atomic Models · easy · theory
In Rutherford's α-particle scattering experiment, the metal foil used was made of:
A. Gold  ✓ Correct
B. Copper
C. Silver
D. Iron
Solution: Rutherford (with Geiger and Marsden) bombarded a very thin gold foil with α-particles.
Q17 — Atomic Models · easy · theory
In the α-scattering experiment, the observation that most α-particles passed straight through the foil showed that:
A. The atom is mostly empty space  ✓ Correct
B. α-particles are negatively charged
C. The atom has a large negative core
D. The electrons are at the centre
Solution: Since the vast majority of α-particles went through undeflected, most of the atom's volume must be empty space.
Q18 — Atomic Models · easy · theory
The atomic number (Z) of an element is equal to the number of:
A. Protons in the nucleus  ✓ Correct
B. Electrons in the outermost shell
C. Protons and neutrons
D. Neutrons in the nucleus
Solution: The atomic number Z is the number of protons in the nucleus (equal to the number of electrons in a neutral atom).
Q19 — Atomic Models · easy · theory
The mass number (A) of an atom is given by:
A. Number of protons only
B. Number of electrons + number of protons
C. Number of neutrons − number of protons
D. Number of protons + number of neutrons  ✓ Correct
Solution: Mass number A = number of protons (Z) + number of neutrons (N). Neutrons = A − Z.
Q20 — Atomic Models · easy · theory
Isotopes of an element have the same:
A. Atomic number but different mass number  ✓ Correct
B. Number of neutrons
C. Mass number but different atomic number
D. Number of protons and neutrons
Solution: Isotopes have the same number of protons (same Z) but different numbers of neutrons, so different mass numbers.
Q21 — Atomic Models · easy · theory
Isobars are atoms that have the same:
A. Number of neutrons
B. Number of protons
C. Atomic number but different mass number
D. Mass number but different atomic number  ✓ Correct
Solution: Isobars have the same mass number A but different atomic numbers Z (different elements).
Q22 — Atomic Models · easy · theory
The major drawback of Rutherford's nuclear model of the atom was that it could not explain the:
A. Stability of the atom  ✓ Correct
B. Presence of electrons
C. Existence of the nucleus
D. Neutral nature of the atom
Solution: Rutherford's model could not account for why the revolving electron does not lose energy and collapse into the nucleus — i.e. atomic stability.
Q23 — Atomic Models · easy · theory
The nucleus of an atom contains:
A. Protons and neutrons  ✓ Correct
B. Protons and electrons
C. Only protons
D. Electrons and neutrons
Solution: The nucleus is made up of protons and neutrons (collectively called nucleons); electrons revolve around it.
Q24 — Atomic Models · easy · numerical
An element X has 17 protons and 18 neutrons. Its mass number is:
A. 35  ✓ Correct
B. 17
C. 1
D. 18
Solution: Mass number A = protons + neutrons = 17 + 18 = 35.
Q25 — Developments Leading to Bohr's Model · easy · theory
The relationship between the speed (c), frequency (ν) and wavelength (λ) of electromagnetic radiation is:
A. c = λ/ν
B. ν = cλ
C. c = ν/λ
D. c = νλ  ✓ Correct
Solution: For any electromagnetic wave, speed = frequency × wavelength, i.e. c = νλ.
Q26 — Developments Leading to Bohr's Model · easy · theory
The wavenumber (ν̄) of radiation is defined as:
A. The speed of light divided by frequency
B. The reciprocal of frequency
C. The reciprocal of wavelength (1/λ)  ✓ Correct
D. The product of ν and λ
Solution: Wavenumber ν̄ = 1/λ, the number of waves per unit length (units m⁻¹ or cm⁻¹).
Q27 — Developments Leading to Bohr's Model · easy · theory
Which of the following electromagnetic radiations has the highest frequency?
A. Ultraviolet
B. X-rays
C. γ-rays  ✓ Correct
D. Infrared
Solution: γ-rays have the shortest wavelength and therefore the highest frequency (and energy) among the given radiations.
Q28 — Developments Leading to Bohr's Model · easy · theory
Which of the following has the longest wavelength?
A. Microwaves
B. Visible light
C. X-rays
D. Radio waves  ✓ Correct
Solution: Radio waves have the longest wavelength (and lowest frequency) in the electromagnetic spectrum.
Q29 — Developments Leading to Bohr's Model · easy · theory
According to Planck's quantum theory, energy is emitted or absorbed only in discrete packets called:
A. Quanta (photons)  ✓ Correct
B. Orbitals
C. Nodes
D. Electrons
Solution: Planck proposed that radiant energy is emitted/absorbed in whole-number multiples of a quantum, E = hν (a quantum of light is a photon).
Q30 — Developments Leading to Bohr's Model · easy · theory
In the equation E = hν, the constant h is the:
A. Rydberg constant
B. Planck constant (6.626 × 10⁻³⁴ J s)  ✓ Correct
C. Speed of light
D. Avogadro number
Solution: h is Planck's constant, 6.626 × 10⁻³⁴ J s, relating a photon's energy to its frequency.