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Chemical Bonding — NEET Chemistry MCQs with Solutions

Free NEET Chemistry Chemical Bonding MCQs with step-by-step solutions covering Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment, VSEPR Theory, Valence Bond Theory and Hybridisation, Molecular Orbital Theory and Hydrogen Bonding. Practise online on Prepizo — no login needed.

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Sample questions with solutions

Q1 — easy
Which among the following shows the limitation of Lewis octet rule ?
A. CH₄
B. NO  ✓ Correct
C. CO₂
D. NH₄⁺
Q2 — easy
Which of the following is an example of expanded octet ?
A. SF₆
B. PF₅
C. H₂SO₄
D. All of these  ✓ Correct
Q3 — easy
p–p overlapping will be observed in the molecules of:
A. Hydrogen
B. Hydrogen bromide
C. Hydrogen chloride
D. Chlorine  ✓ Correct
Q4 — easy
π bond is formed :-
A. By overlapping of hybridised orbitals
B. Overlapping of s - s orbitals
C. Head on overlapping of p -p orbitals
D. By p - p collateral overlapping  ✓ Correct
Q5 — easy
Which of the following has pyramidal shape ?
A. BF₃
B. H₃O⁺  ✓ Correct
C. NO₃⁻
D. CO₃²⁻
Q6 — easy
A sigma bond is formed by the overlapping of :–
A. s-s orbital alone
B. s and p orbitals alone
C. s–s, s–p or p–p orbitals along internuclear axis  ✓ Correct
D. p–p orbital along the sides
Q7 — easy
The molecule does not have bent shape :-
A. SO₂
B. O₃
C. H₂O
D. NH₄⁺  ✓ Correct
Q8 — easy
Which overlapping is involved in HCl molecule :–
A. s–s overlap
B. p–p overlap
C. s–d overlap
D. s–p overlap  ✓ Correct
Q9 — easy
BeF₂ has zero dipole moment where as H₂O has a dipole moment because :-
A. Water is linear
B. H₂O is bent  ✓ Correct
C. F is more electronegative than O
D. Hydrogen bonding is present in H₂O
Q10 — easy
Which of the following molecule have zero dipole moment:-
A. BF₃  ✓ Correct
B. CH₂Cl₂
C. NF₃
D. SO₂
Q11 — easy
Which of the following has zero dipole moment :
A. PCl₃
B. CH₂Cl₂
C. CHCl₃
D. CCl₄  ✓ Correct
Q12 — easy
Dipole moment of CO₂ is zero which implies that :
A. Carbon and oxygen have equal electronegativities
B. Carbon has no polar bond
C. CO₂ is a linear molecule  ✓ Correct
D. Carbon has bond moments of zero value
Q13 — easy
The molecule does not have zero dipole moment :-
A. CO₂
B. CCl₄
C. BF₃
D. HCl  ✓ Correct
Q14 — easy
Which of the following compound possess dipole moment :-
A. Water  ✓ Correct
B. Boron trifluoride
C. Benzene
D. Carbon tetra chloride
Q15 — easy
In Co-ordinate bond, the acceptor atoms must essentially contain in its valence shell an orbital:-
A. With paired electron
B. With single electron
C. With no electron  ✓ Correct
D. With three electron
Q16 — easy
Intermolecular hydrogen bonds are not present in:-
A. CH₃CH₂OH
B. CH₃COOH
C. C₂H₅NH₂
D. CH₃OCH₃  ✓ Correct
Q17 — easy
Dative bond is present in
A. SO₃  ✓ Correct
B. NH₃
C. K₂CO₃
D. BF₃
Q18 — easy
NH₃ has abnormally high boiling point because it has :
A. Alkaline nature
B. Distorted shape
C. sp³ - Hybridisation
D. Hydrogen bonding  ✓ Correct
Q19 — easy
Maximum no. of hydrogen bonds formed by a water molecule in ice is
A. 4  ✓ Correct
B. 3
C. 2
D. 1
Q20 — easy
Which of the following is soluble in water ?
A. CS₂
B. C₂H₅OH  ✓ Correct
C. CCl₄
D. CHCl₃
Q21 — easy
The force responsible for dissolution of ionic compound in water is –
A. Dipole – dipole forces
B. Ion – dipole force  ✓ Correct
C. Ion – ion force
D. Hydrogen bond
Q22 — easy
As compared to covalent compounds electrovalent compounds generally possess
A. High m.p. and high b.p.  ✓ Correct
B. Low m.p. and low b.p.
C. Low m.p. and high b.p.
D. high m.p. and low b.p.
Q23 — easy
Which of the following does not show electrical conduction ?
A. diamond  ✓ Correct
B. graphite
C. sodium chloride (fused)
D. potassium
Q24 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
Which one of the following molecules has maximum dipole moment?
A. NH₃  ✓ Correct
B. PF₅
C. CH₄
D. NF₃
Solution: PF₅ (trigonal bipyramidal) and CH₄ (tetrahedral) are symmetric with zero dipole moment. In NH₃ the lone-pair moment adds to the N–H bond moments (μ ≈ 1.47 D), while in NF₃ it opposes the N–F moments (μ ≈ 0.24 D). So NH₃ has the maximum dipole moment.
Q25 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
Choose the polar molecule from the following.
A. CH₂=CH₂
B. CHCl₃  ✓ Correct
C. CCl₄
D. CO₂
Solution: CH₂=CH₂, CCl₄ and CO₂ are symmetric, so their bond moments cancel (μ = 0). In CHCl₃ the tetrahedral symmetry is broken (three C–Cl and one C–H), giving a net dipole moment (~1.04 D).
Q26 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
Which of the following is least ionic?
A. CoCl₂
B. KCl
C. BaCl₂
D. AgCl  ✓ Correct
Solution: By Fajan's rules, Ag⁺ has a pseudo noble-gas (18-electron) configuration, giving it much higher polarizing power than K⁺, Ba²⁺ or Co²⁺ of comparable charge. AgCl is therefore the most covalent, i.e. least ionic.
Q27 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
The carbonate ion CO₃²⁻ is represented by three resonance (canonical) structures. Which of the following is true?
A. All these structures are in dynamic equilibrium with each other.
B. Each structure exists for an equal amount of time.
C. CO₃²⁻ has a single structure, i.e. a resonance hybrid of the three structures.  ✓ Correct
D. It is possible to identify each structure individually by some physical or chemical method.
Solution: Canonical structures have no real, independent existence — they are not in equilibrium and cannot be isolated or detected. The ion has one actual structure, the resonance hybrid, in which all three C–O bonds are identical.
Q28 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
Which of the following pairs of molecules contains an odd-electron molecule and an expanded-octet molecule?
A. BCl₃ and SF₆
B. NO and H₂SO₄  ✓ Correct
C. SF₆ and H₂SO₄
D. BCl₃ and NO
Solution: NO has 11 valence electrons (odd-electron molecule). In H₂SO₄ sulphur is surrounded by 12 electrons (expanded octet). BCl₃ is electron deficient (incomplete octet), and SF₆/H₂SO₄ are both expanded octets — neither of those pairs has an odd-electron member.
Q29 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
The number of electron-deficient molecules among the following — PH₃, B₂H₆, CCl₄, NH₃, LiH and BCl₃ — is
A. 0
B. 1
C. 2  ✓ Correct
D. 3
Solution: B₂H₆ (banana 3c–2e bonds) and BCl₃ (boron has only 6 electrons) are electron deficient. PH₃, NH₃, CCl₄ have complete octets, and LiH is ionic — so the count is 2. (JEE Main 2022)
Q30 — Ionic and Covalent Bonding, Fajan's Rule and Dipole Moment · easy
The dipole moments of CCl₄, CHCl₃ and CH₄ are in the order
A. CH₄ = CCl₄ < CHCl₃  ✓ Correct
B. CHCl₃ < CH₄ = CCl₄
C. CH₄ < CCl₄ < CHCl₃
D. CCl₄ < CH₄ < CHCl₃
Solution: CH₄ and CCl₄ are perfectly tetrahedral, so their bond moments cancel and both have μ = 0. CHCl₃ is unsymmetrical and polar. Hence CH₄ = CCl₄ (= 0) < CHCl₃. (NEET 2020)