Ionization Enthalpy & Electron Gain Enthalpy — NEET Chemistry MCQs with Solutions
Free NEET Chemistry Ionization Enthalpy & Electron Gain Enthalpy MCQs with step-by-step solutions (40 questions). Part of Classification of Elements and Periodicity. Practise online on Prepizo — no login needed.
▶ Practise Ionization Enthalpy & Electron Gain Enthalpy online (free)
Questions with solutions
Q1 — Ionization Enthalpy & Electron Gain Enthalpy · easy · theory
Ionization enthalpy is the energy required to remove the most loosely bound electron from an isolated ______ atom:
A. Liquid
B. Solid
C. Aqueous
D. Gaseous ✓ Correct
Solution: ΔᵢH refers to removal of an electron from a neutral gaseous atom.
Q2 — Ionization Enthalpy & Electron Gain Enthalpy · easy · theory
Across a period, the first ionization enthalpy generally:
A. Increases ✓ Correct
B. Decreases
C. Stays constant
D. First increases then decreases sharply
Solution: Rising Z_eff and shrinking size make electron removal harder across a period.
Q3 — Ionization Enthalpy & Electron Gain Enthalpy · easy · theory
Down a group, the first ionization enthalpy generally:
A. Stays constant
B. Increases
C. First decreases then increases
D. Decreases ✓ Correct
Solution: Larger size and greater shielding make the outer electron easier to remove down a group.
Q4 — Ionization Enthalpy & Electron Gain Enthalpy · easy · theory
The order of successive ionization enthalpies of an element is:
A. ΔᵢH₁ > ΔᵢH₂ > ΔᵢH₃
B. ΔᵢH₂ < ΔᵢH₁
C. All equal
D. ΔᵢH₁ < ΔᵢH₂ < ΔᵢH₃ ✓ Correct
Solution: Removing electrons from an increasingly positive ion needs progressively more energy.
Q5 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Beryllium has a higher first ionization enthalpy than boron because Be has a:
A. Half-filled 2p subshell
B. Lower nuclear charge
C. Larger size
D. Stable, fully-filled 2s² configuration ✓ Correct
Solution: Removing an electron from the extra-stable 2s² of Be is harder than from the 2p¹ of B.
Q6 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Nitrogen has a higher first ionization enthalpy than oxygen because N has a:
A. Smaller size
B. Larger nuclear charge
C. Fully-filled 2p subshell
D. Stable half-filled 2p³ configuration ✓ Correct
Solution: The half-filled 2p³ of N is extra stable, so it resists losing an electron more than O's 2p⁴.
Q7 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
A large jump between two successive ionization enthalpies indicates:
A. The presence of isotopes
B. A measurement error
C. Removal of an electron from a stable noble-gas core (revealing the valency) ✓ Correct
D. The atom has become larger
Solution: The sudden jump appears after all valence electrons are gone, so its position reveals the group/valency.
Q8 — Ionization Enthalpy & Electron Gain Enthalpy · easy · theory
Noble gases have the highest ionization enthalpies in their periods because of their:
A. Stable, completely-filled (octet) configuration ✓ Correct
B. Low nuclear charge
C. Large size
D. Metallic character
Solution: The fully-filled ns²np⁶ shell is very stable, so removing an electron requires the most energy.
Q9 — Ionization Enthalpy & Electron Gain Enthalpy · easy · theory
Electron gain enthalpy is the enthalpy change when an electron is added to a neutral gaseous atom; a negative value means the process is:
A. Athermal
B. Endothermic
C. Impossible
D. Exothermic (energy released) ✓ Correct
Solution: A negative Δₑ𝓰H means energy is released on adding the electron.
Q10 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Chlorine has a more negative electron gain enthalpy than fluorine because:
A. Cl has fewer protons
B. F has a larger size
C. F's small, compact 2p subshell causes greater electron–electron repulsion on the added electron ✓ Correct
D. F is a metal
Solution: The incoming electron enters F's very compact 2p, facing high repulsion; Cl's larger 3p accommodates it better — so Δₑ𝓰H(Cl) is more negative.
Q11 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Elements with positive (endothermic) electron gain enthalpy include:
A. Noble gases, Be, Mg and N ✓ Correct
B. Halogens
C. Alkali metals
D. Chalcogens
Solution: Stable filled/half-filled shells (noble gases, ns² of Be/Mg, half-filled 2p³ of N) resist gaining an electron.
Q12 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
The factor that does NOT increase ionization enthalpy is:
A. Increasing nuclear charge
B. Stable half/fully-filled configuration
C. Increasing atomic size ✓ Correct
D. Increasing Z_eff
Solution: Larger size lowers IE; the others all raise it.
Q13 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
The penetration power of orbitals, which affects ionization enthalpy, follows the order:
A. p > s > d > f
B. d > p > s > f
C. s > p > d > f ✓ Correct
D. f > d > p > s
Solution: s electrons penetrate closest to the nucleus, so they are held most tightly.
Q14 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Across period 2, sulphur (period 3) shows a more negative Δₑ𝓰H than oxygen because:
A. S has a smaller nuclear charge
B. O's compact 2p causes more repulsion on the incoming electron than S's larger 3p ✓ Correct
C. O is a metal
D. S has fewer electrons
Solution: Like Cl>F, the anomaly S>O arises from the compactness of the 2p subshell in oxygen.
Q15 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Down a group, electron gain enthalpy generally becomes:
A. Zero
B. More negative always
C. Positive for all
D. Less negative (with the F < Cl exception) ✓ Correct
Solution: Larger size means the added electron is less strongly attracted, so Δₑ𝓰H is less negative down a group (fluorine being the notable exception).
Q16 — Ionization Enthalpy & Electron Gain Enthalpy · medium · theory
Electron gain enthalpy differs from electronegativity in that electron gain enthalpy is:
A. Always positive
B. The same thing
C. Defined only for metals
D. A measurable enthalpy for an isolated gaseous atom, while electronegativity is a relative tendency in a bond ✓ Correct
Solution: Δₑ𝓰H is a thermodynamic quantity for a free atom; electronegativity describes attraction for shared electrons within a molecule.
Q17 — Ionization Enthalpy & Electron Gain Enthalpy · medium · numerical
The correct order of first ionization enthalpy for Li, Be, B, C (period 2) is:
A. Li < Be < B < C
B. Li < B < Be < C ✓ Correct
C. C < B < Be < Li
D. Be < Li < B < C
Solution: General rise, but Be(2s²) > B(2p¹): order Li < B < Be < C.
Q18 — Ionization Enthalpy & Electron Gain Enthalpy · easy · numerical
Which element has a higher first ionization enthalpy: N or O?
A. Both equal
B. Cannot be said
C. O
D. N ✓ Correct
Solution: N's half-filled 2p³ is extra stable, so ΔᵢH(N) > ΔᵢH(O) — a classic anomaly.
Q19 — Ionization Enthalpy & Electron Gain Enthalpy · easy · numerical
Which has the higher first ionization enthalpy: Mg or Al?
A. Depends on temperature
B. Both equal
C. Al
D. Mg ✓ Correct
Solution: Mg's filled 3s² is stable; Al loses its lone 3p¹ more easily ⇒ ΔᵢH(Mg) > ΔᵢH(Al).
Q20 — Ionization Enthalpy & Electron Gain Enthalpy · hard · numerical
The successive ionization enthalpies (kJ/mol) of an element are 738, 1451, 7733, 10540. The element most likely belongs to group:
A. 2 ✓ Correct
B. 3
C. 13
D. 1
Solution: A huge jump after the 2nd ionization means 2 easily-removed valence electrons ⇒ group 2 (this is Mg).
Q21 — Ionization Enthalpy & Electron Gain Enthalpy · hard · numerical
For an element with ΔᵢH values 496, 4562, 6912 kJ/mol, the group is:
A. 13
B. 17
C. 2
D. 1 ✓ Correct
Solution: A sharp jump after the 1st IE means 1 valence electron ⇒ group 1 (this is Na).
Q22 — Ionization Enthalpy & Electron Gain Enthalpy · medium · numerical
The correct decreasing order of first ionization enthalpy of Na, Mg, Al is:
A. Mg > Al > Na ✓ Correct
B. Na > Mg > Al
C. Al > Mg > Na
D. Mg > Na > Al
Solution: Across period 3 IE rises (Na<Al) but Mg(3s²) > Al ⇒ Mg > Al > Na.
Q23 — Ionization Enthalpy & Electron Gain Enthalpy · easy · numerical
Which has the more negative (higher magnitude) electron gain enthalpy: F or Cl?
A. Cl ✓ Correct
B. Neither gains electrons
C. Both equal
D. F
Solution: Cl > F because the incoming electron faces less repulsion in Cl's larger 3p subshell.
Q24 — Ionization Enthalpy & Electron Gain Enthalpy · medium · numerical
The total energy to convert one mole of gaseous Mg to Mg²⁺, given ΔᵢH₁ = 738 and ΔᵢH₂ = 1451 kJ/mol, is:
A. 2189 kJ/mol ✓ Correct
B. 3640 kJ/mol
C. 713 kJ/mol
D. 1451 kJ/mol
Solution: Total = ΔᵢH₁ + ΔᵢH₂ = 738 + 1451 = 2189 kJ/mol.
Q25 — Ionization Enthalpy & Electron Gain Enthalpy · easy · numerical
The correct order of first ionization enthalpy for the noble gases He, Ne, Ar is:
A. He > Ar > Ne
B. Ar > Ne > He
C. He > Ne > Ar ✓ Correct
D. Ne > He > Ar
Solution: IE decreases down group 18 as size increases ⇒ He > Ne > Ar.
Q26 — Ionization Enthalpy & Electron Gain Enthalpy · easy · numerical
The energy needed to remove one electron each from a mole of gaseous Al atoms (ΔᵢH₁ = 577 kJ/mol) to form Al⁺ is:
A. 288 kJ/mol
B. 5770 kJ/mol
C. 577 kJ/mol ✓ Correct
D. 1154 kJ/mol
Solution: Removing the first electron requires ΔᵢH₁ = 577 kJ/mol.
Q27 — Ionization Enthalpy & Electron Gain Enthalpy · medium · numerical
Which of the following has the most negative electron gain enthalpy?
A. I
B. F
C. Cl ✓ Correct
D. Br
Solution: Chlorine has the most negative Δₑ𝓰H of all elements (Cl > F due to F's compactness).
Q28 — Ionization Enthalpy & Electron Gain Enthalpy · medium · numerical
The pair in which the first element has a HIGHER ionization enthalpy (an anomaly) is:
A. B and C
B. P and S (P > S) ✓ Correct
C. Li and Be
D. C and N
Solution: P (half-filled 3p³) has a higher ΔᵢH than S — the P > S anomaly.
Q29 — Ionization Enthalpy & Electron Gain Enthalpy · hard · numerical
The successive ΔᵢH (kJ/mol) 578, 1817, 2745, 11577 indicate the element is in group:
A. 2
B. 3
C. 13 ✓ Correct
D. 14
Solution: Large jump after the 3rd IE ⇒ 3 valence electrons ⇒ group 13 (this is Al).
Q30 — Ionization Enthalpy & Electron Gain Enthalpy · hard · numerical
Arrange O, S, Se by increasingly negative electron gain enthalpy correctly (most negative first):
A. S > O > Se
B. O > S > Se
C. S > Se > O ✓ Correct
D. Se > S > O
Solution: S has the most negative Δₑ𝓰H (S > O anomaly); then Se, with O least due to 2p compactness.