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Properties of Matter & Measurement — NEET Chemistry MCQs with Solutions

Free NEET Chemistry Properties of Matter & Measurement MCQs with step-by-step solutions (7 questions). Part of Some Basic Concepts of Chemistry. Practise online on Prepizo — no login needed.

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Questions with solutions

Q1 — Properties of Matter & Measurement · easy · theory
Which one of the following is a PHYSICAL property of a substance?
A. Reactivity with acids
B. Combustibility
C. Acidity
D. Density  ✓ Correct
Solution: Physical properties such as colour, odour, melting point, boiling point and density can be measured or observed without changing the identity or composition of the substance. Combustibility, reactivity with acids and acidity all require a chemical change to be observed, so they are chemical properties.
Q2 — Properties of Matter & Measurement · easy · theory
Which of the following statements about mass and weight is correct?
A. The weight of a substance is constant, but its mass varies with gravity
B. The mass of a substance is constant, but its weight may vary from one place to another  ✓ Correct
C. Mass and weight are the same physical quantity measured in different units
D. Mass is the force exerted by gravity on an object
Solution: Mass is the amount of matter present in a substance and stays constant everywhere. Weight is the force exerted by gravity on the object, so it can change from place to place as gravity changes. Hence only the first statement is correct.
Q3 — Properties of Matter & Measurement · easy · numerical
A block of metal has a mass of 60 g and occupies a volume of 20 cm³. Using density = mass ÷ volume, its density is:
A. 0.33 g cm⁻³
B. 3 g cm⁻³  ✓ Correct
C. 1200 g cm⁻³
D. 30 g cm⁻³
Solution: Density = mass ÷ volume = 60 g ÷ 20 cm³ = 3 g cm⁻³. Inverting the ratio (20 ÷ 60) gives the wrong 0.33 g cm⁻³, while multiplying (60 × 20) gives 1200 g cm⁻³.
Q4 — Properties of Matter & Measurement · easy · numerical
The volume of a liquid is 2.5 L. Using 1 L = 1000 cm³, this volume expressed in cm³ is:
A. 2500 cm³  ✓ Correct
B. 250 cm³
C. 25 cm³
D. 25000 cm³
Solution: Since 1 L = 1000 cm³, 2.5 L = 2.5 × 1000 = 2500 cm³. Using a factor of 100 gives 250, and a factor of 10000 gives 25000 — both are wrong powers of ten.
Q5 — Properties of Matter & Measurement · medium · numerical
Normal human body temperature is 37 °C. Using °F = (9/5)°C + 32, this temperature on the Fahrenheit scale is:
A. 66.6 °F
B. 98.6 °F  ✓ Correct
C. 310.15 °F
D. 88.6 °F
Solution: °F = (9/5)(37) + 32 = 66.6 + 32 = 98.6 °F. Forgetting to add 32 leaves 66.6 °F, and 310.15 is the kelvin value (37 + 273.15), not the Fahrenheit reading.
Q6 — Properties of Matter & Measurement · easy · numerical
A liquid has a density of 0.8 g cm⁻³. Using mass = density × volume, the mass of 50 cm³ of this liquid is:
A. 40 g  ✓ Correct
B. 0.016 g
C. 62.5 g
D. 400 g
Solution: mass = density × volume = 0.8 g cm⁻³ × 50 cm³ = 40 g. Dividing volume by density (50 ÷ 0.8) gives the wrong 62.5 g.
Q7 — Properties of Matter & Measurement · medium · numerical
A temperature of −23 °C, expressed on the kelvin scale using K = °C + 273.15, is:
A. 250.15 K  ✓ Correct
B. 296.15 K
C. 300.15 K
D. 273.15 K
Solution: K = °C + 273.15 = (−23) + 273.15 = 250.15 K. Ignoring the negative sign and adding +23 gives the wrong 296.15 K; 273.15 K corresponds to 0 °C.