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Nuclear Fission & Fusion and Binding Energy — NEET Physics PYQ MCQs with Solutions
Free NEET Physics PYQ Nuclear Fission & Fusion and Binding Energy MCQs with step-by-step solutions (32 questions). Part of Nuclei. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the binding energy in the process is
A. 0.9 MeV
B. 9.4 MeV
C. 804 MeV
D. 216 MeV ✓ Correct
Solution: Gain $= 2 \times 120 \times 8.5 - 240 \times 7.6 = 2040 - 1824 = 216$ MeV
Q2 — Nuclear Fission & Fusion and Binding Energy · easy · numerical
The energy equivalent of 0.5 g of a substance is
A. $4.5 \times 10^{13}$ J ✓ Correct
B. $1.5 \times 10^{13}$ J
C. $0.5 \times 10^{13}$ J
D. $4.5 \times 10^{16}$ J
Solution: $E = mc^2 = 0.5 \times 10^{-3} \times (3 \times 10^8)^2 = 4.5 \times 10^{13}$ J
Q3 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
When a uranium isotope $^{235}_{92}$U is bombarded with a neutron, it generates $^{89}_{36}$Kr, three neutrons and
A. $^{91}_{40}$Zr
B. $^{101}_{36}$Kr
C. $^{103}_{36}$Kr
D. $^{144}_{56}$Ba ✓ Correct
Solution: Charge: $Z = 92 - 36 = 56$; mass: $A = 235 + 1 - 89 - 3 = 144$
The other product is $^{144}_{56}$Ba.
Q4 — Nuclear Fission & Fusion and Binding Energy · medium · theory
A nucleus of uranium decays at rest into nuclei of thorium and helium. Then,
A. the helium nucleus has more kinetic energy than the thorium nucleus ✓ Correct
B. the helium nucleus has less momentum than the thorium nucleus
C. the helium nucleus has more momentum than the thorium nucleus
D. the helium nucleus has less kinetic energy than the thorium nucleus
Solution: Momentum conservation gives both fragments equal and opposite momenta. Since $KE = \frac{p^2}{2m}$ and $m_{He} < m_{Th}$, the helium nucleus has more kinetic energy.
Q5 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
The binding energy per nucleon of $^{7}_{3}$Li and $^{4}_{2}$He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction $^{7}_{3}Li + ^{1}_{1}H \rightarrow\ ^{4}_{2}He + ^{4}_{2}He + Q$, the value of energy Q released is
A. 19.6 MeV
B. −2.4 MeV
C. 8.4 MeV
D. 17.3 MeV ✓ Correct
Solution: $Q = 2(4 \times 7.06) - (7 \times 5.60) = 56.48 - 39.2 = 17.3$ MeV
Q6 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)
A. 2.67 MeV
B. 26.7 MeV
C. 6.675 MeV ✓ Correct
D. 13.35 MeV
Solution: Energy liberated $= 0.02866 \times 931 = 26.7$ MeV
Per u (A = 4): $\frac{26.7}{4} = 6.675$ MeV
Q7 — Nuclear Fission & Fusion and Binding Energy · easy · theory
Fusion reaction takes place at high temperature because
A. atoms get ionised at high temperature
B. kinetic energy is high enough to overcome the coulomb repulsion between nuclei ✓ Correct
C. molecules break up at high temperature
D. nuclei break up at high temperature
Solution: At high temperature the kinetic energy of the nuclei is high enough to overcome the Coulomb repulsion between them, allowing fusion.
Q8 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
The mass of a $^{7}_{3}$Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of $^{7}_{3}$Li nucleus is nearly
A. 46 MeV
B. 5.6 MeV ✓ Correct
C. 3.9 MeV
D. 23 MeV
Solution: Binding energy $= 0.042 \times 931 = 39.1$ MeV
Per nucleon: $\frac{39.1}{7} \approx 5.6$ MeV
Q9 — Nuclear Fission & Fusion and Binding Energy · medium · theory
A nucleus $^{A}_{Z}X$ has mass represented by m(A, Z). If $m_p$ and $m_n$ denote the mass of proton and neutron respectively and BE the binding energy (in MeV), then
A. $BE = [m(A, Z) - Zm_p - (A - Z)m_n]c^2$
B. $BE = [Zm_p + (A - Z)m_n - m(A, Z)]c^2$ ✓ Correct
C. $BE = [Zm_p + Am_n - m(A, Z)]c^2$
D. $BE = m(A, Z) - Zm_p - (A - Z)m_n$
Solution: The mass defect is $\Delta m = Zm_p + (A - Z)m_n - m(A, Z)$, so
$BE = [Zm_p + (A - Z)m_n - m(A, Z)]c^2$
Q10 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
The binding energy of deuteron is 2.2 MeV and that of $^{4}_{2}$He is 28 MeV. If two deuterons are fused to form one $^{4}_{2}$He, then the energy released is
A. 25.8 MeV
B. 23.6 MeV ✓ Correct
C. 19.2 MeV
D. 30.2 MeV
Solution: Energy released = BE of products − BE of reactants
$= 28 - 2 \times 2.2 = 23.6$ MeV
Q11 — Nuclear Fission & Fusion and Binding Energy · medium · theory
In any fission process the ratio $\frac{\text{mass of fission products}}{\text{mass of parent nucleus}}$ is
A. less than 1 ✓ Correct
B. greater than 1
C. equal to 1
D. depends on the mass of parent nucleus
Solution: In fission some mass is converted into energy, so the total mass of the fission products is less than that of the parent nucleus — the ratio is less than 1.
Q12 — Nuclear Fission & Fusion and Binding Energy · medium · theory
Fission of nuclei is possible because the binding energy per nucleon in them
A. increases with mass number at high mass numbers
B. decreases with mass number at high mass numbers ✓ Correct
C. increases with mass number at low mass numbers
D. decreases with mass number at low mass numbers
Solution: For heavy nuclides the binding energy per nucleon decreases with increasing mass number, making them relatively unstable and fissionable.
Q13 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
In the reaction $^{2}_{1}H + ^{3}_{1}H \rightarrow\ ^{4}_{2}He + ^{1}_{0}n$, if the binding energies of $^{2}_{1}$H, $^{3}_{1}$H and $^{4}_{2}$He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is
A. $c + a - b$
B. $c - a - b$ ✓ Correct
C. $a + b + c$
D. $a + b - c$
Solution: Energy released = BE of products − BE of reactants $= c - (a + b) = c - a - b$
Q14 — Nuclear Fission & Fusion and Binding Energy · medium · theory
$m_p$ denotes the mass of a proton and $m_n$ that of a neutron. A given nucleus of binding energy BE, contains Z protons and N neutrons. The mass m(N, Z) of the nucleus is given by
A. $m(N, Z) = Nm_n + Zm_p - BEc^2$
B. $m(N, Z) = Nm_n + Zm_p + BEc^2$
C. $m(N, Z) = Nm_n + Zm_p - BE/c^2$ ✓ Correct
D. $m(N, Z) = Nm_n + Zm_p + BE/c^2$
Solution: $BE = [Nm_n + Zm_p - m(N, Z)]c^2$
$m(N, Z) = Nm_n + Zm_p - \frac{BE}{c^2}$
Q15 — Nuclear Fission & Fusion and Binding Energy · easy · theory
If in a nuclear fusion process, the masses of the fusing nuclei be $m_1$ and $m_2$ and the mass of the resultant nucleus be $m_3$, then
A. $m_3 = m_1 + m_2$
B. $m_3 = |m_1 - m_2|$
C. $m_3 < (m_1 + m_2)$ ✓ Correct
D. $m_3 > (m_1 + m_2)$
Solution: In fusion some mass (the mass defect) is converted into released energy, so $m_3 < m_1 + m_2$.
Q16 — Nuclear Fission & Fusion and Binding Energy · easy · theory
Solar energy is mainly caused due to
A. fusion of protons during synthesis of heavier elements ✓ Correct
B. gravitational contraction
C. burning of hydrogen in the oxygen
D. fission of uranium present in the sun
Solution: In the sun, energy is produced by the fusion of four protons (hydrogen nuclei) into a helium nucleus, releasing enormous energy.
Q17 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of $^{4}_{2}$He is (mass of helium nucleus = 4.0015 u)
A. 28.4 MeV ✓ Correct
B. 0.061 u
C. 0.0305 J
D. 0.0305 erg
Solution: $\Delta m = (2 \times 1.0073 + 2 \times 1.0087) - 4.0015 = 0.0305$ u
$BE = 0.0305 \times 931 = 28.4$ MeV
Q18 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
When a deuterium is bombarded on $^{16}_{8}$O nucleus, an $\alpha$-particle is emitted, then the product nucleus is
A. $^{13}_{7}$N
B. $^{10}_{5}$B
C. $^{9}_{4}$Be
D. $^{14}_{7}$N ✓ Correct
Solution: $^{16}_{8}O + ^{2}_{1}H \rightarrow\ ^{A}_{Z}X + ^{4}_{2}He$
Mass: $A = 16 + 2 - 4 = 14$; charge: $Z = 8 + 1 - 2 = 7$ — nitrogen $^{14}_{7}$N.
Q19 — Nuclear Fission & Fusion and Binding Energy · easy · theory
Which of the following are suitable for the fusion process?
A. Light nuclei ✓ Correct
B. Heavy nuclei
C. Elements lying in the middle of periodic table
D. Elements lying in the middle of binding energy curve
Solution: Light nuclei (A < 20) have relatively small binding energy per nucleon; combining them into a heavier nucleus raises it and liberates a large amount of energy.
Q20 — Nuclear Fission & Fusion and Binding Energy · medium · theory
In nuclear fission process, energy is released because
A. mass of products is more than mass of nucleus
B. total binding energy of products formed due to nuclear fission is more than the parent fissionable material ✓ Correct
C. total binding energy of products formed due to nuclear fission is less than parent fissionable material
D. mass of some particles is converted into energy
Solution: Energy is released when the binding energy per nucleon of the products increases — the total binding energy of the fission products exceeds that of the parent nucleus.
Q21 — Nuclear Fission & Fusion and Binding Energy · easy · theory
$m_p$ and $m_n$ are masses of proton and neutron respectively. An element of mass m has Z protons and N neutrons, then
A. $m > Zm_p + Nm_n$
B. $m = Zm_p + Nm_n$
C. $m < Zm_p + Nm_n$ ✓ Correct
D. m may be greater than, less than or equal to $Zm_p + Nm_n$, depending on nature of element
Solution: The nuclear mass is always slightly less than the sum of the masses of its constituent nucleons — the difference is the mass defect (binding energy).
Q22 — Nuclear Fission & Fusion and Binding Energy · medium · theory
Nuclear fission can be explained by
A. proton-proton cycle
B. liquid drop model of nucleus ✓ Correct
C. independent nuclear particle model
D. nuclear shell model
Solution: Bohr and Wheeler explained fission with the liquid drop model: the struggle between surface tension and excitation energy deforms the nucleus until Coulomb repulsion tears it apart.
Q23 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
Complete the equation for the following fission process: $^{235}_{92}U + ^{1}_{0}n \rightarrow\ ^{90}_{38}Sr + ...$
A. $^{143}_{54}$Xe + 3$^{1}_{0}$n ✓ Correct
B. $^{145}_{54}$Xe
C. $^{142}_{57}$Xe
D. $^{142}_{54}$Xe + $^{1}_{0}$n
Solution: Balancing: charge $92 = 38 + 54$; mass $236 = 90 + 143 + 3$
The products are $^{143}_{54}$Xe and 3 neutrons.
Q24 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
In a fission reaction $^{236}_{92}U \rightarrow\ ^{117}X + ^{117}Y + n + n$, the binding energy per nucleon of X and Y is 8.5 MeV whereas of $^{236}$U is 7.6 MeV. The total energy liberated will be about
A. 2000 MeV
B. 200 MeV ✓ Correct
C. 2 MeV
D. 1 keV
Solution: Energy $= 234 \times 8.5 - 236 \times 7.6 = 1989 - 1793.6 \approx 195$ MeV $\approx 200$ MeV
Q25 — Nuclear Fission & Fusion and Binding Energy · easy · theory
Which of the following is used as a moderator in nuclear reactors?
A. Plutonium
B. Cadmium
C. Heavy water ✓ Correct
D. Uranium
Solution: Moderators slow down fast neutrons. Heavy water, graphite and beryllium oxide are used; heavy water is the best moderator. (Cadmium is used for control rods.)
Q26 — Nuclear Fission & Fusion and Binding Energy · easy · theory
Heavy water is used as a moderator in a nuclear reactor. The function of the moderator is
A. to control energy released in the reactor
B. to absorb neutrons and stop chain reaction
C. to cool the reactor
D. to slow down the neutrons to thermal energies ✓ Correct
Solution: The moderator slows the fast secondary neutrons produced in fission down to thermal energies, since fission is initiated efficiently only by slow neutrons.
Q27 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
If the binding energy per nucleon in $^{7}_{3}$Li and $^{4}_{2}$He nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction $^{7}_{3}Li + p \rightarrow 2\ ^{4}_{2}He$ is
A. 19.6 MeV
B. 2.4 MeV
C. 8.4 MeV
D. 17.3 MeV ✓ Correct
Solution: Energy $= 2(4 \times 7.06) - 7 \times 5.60 = 56.48 - 39.20 = 17.3$ MeV
Q28 — Nuclear Fission & Fusion and Binding Energy · medium · numerical
Energy released in the fission of a single $^{235}_{92}$U nucleus is 200 MeV. The fission rate of a $^{235}_{92}$U filled reactor operating at a power level of 5 W is
A. $1.56 \times 10^{-10}$ s⁻¹
B. $1.56 \times 10^{11}$ s⁻¹ ✓ Correct
C. $1.56 \times 10^{-16}$ s⁻¹
D. $1.56 \times 10^{-17}$ s⁻¹
Solution: Fission rate $= \frac{5}{200 \times 1.6 \times 10^{-13}} = 1.56 \times 10^{11}$ s⁻¹
Q29 — Nuclear Fission & Fusion and Binding Energy · easy · theory
The binding energy per nucleon is maximum in case of
A. $^{4}_{2}$He
B. $^{56}_{26}$Fe ✓ Correct
C. $^{141}_{56}$Ba
D. $^{235}_{92}$U
Solution: The binding energy curve peaks at about 8.8 MeV per nucleon for $^{56}_{26}$Fe — the most stable nucleus.
Q30 — Nuclear Fission & Fusion and Binding Energy · easy · numerical
The energy equivalent of one atomic mass unit is
A. $1.6 \times 10^{-19}$ J
B. $6.02 \times 10^{23}$ J
C. 931 MeV ✓ Correct
D. 9.31 MeV
Solution: $E = mc^2 = 1.66 \times 10^{-27} \times (3 \times 10^8)^2 \approx 1.49 \times 10^{-10}$ J $\approx 931$ MeV