Banking of Roads & Well of Death — NEET Physics MCQs with Solutions
Free NEET Physics Banking of Roads & Well of Death MCQs with step-by-step solutions (8 questions). Part of Circular Motion. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Banking of Roads & Well of Death · easy · theory
Roads are banked at curves so that:
A. Cars can stop faster
B. A component of the normal reaction provides the centripetal force, reducing reliance on friction ✓ Correct
C. The weight of the car decreases
D. Friction increases
Solution: At the design speed v₀ = √(rg tanθ), N sinθ alone supplies mv²/r — no friction needed.
Q2 — Banking of Roads & Well of Death · medium · theory
At the optimum (design) speed on a banked road, the friction force on the tyres is:
A. Zero ✓ Correct
B. Equal to μN
C. Maximum up the slope
D. Maximum down the slope
Solution: The horizontal component of N exactly meets the centripetal demand, so no frictional force is called upon — minimum tyre wear.
Q3 — Banking of Roads & Well of Death · easy · numerical
A curve of radius 40 m is banked at 45°. The optimum speed is:
A. 40 m/s
B. 14.1 m/s
C. 20 m/s ✓ Correct
D. 10 m/s
Solution: v₀ = √(rg tan45°) = √400 = 20 m/s.
Q4 — Banking of Roads & Well of Death · medium · numerical
A road of radius 50 m is designed for 15 m/s. The required banking angle satisfies tanθ =
A. 0.15
B. 0.30
C. 0.90
D. 0.45 ✓ Correct
Solution: tanθ = v²/rg = 225/500 = 0.45 ⇒ θ ≈ 24°.
Q5 — Banking of Roads & Well of Death · hard · numerical
In a well of death of radius 6.4 m with μ = 0.4 between tyres and wall, the minimum speed of the rider is:
A. ≈ 25.6 m/s
B. ≈ 8 m/s
C. ≈ 12.6 m/s ✓ Correct
D. ≈ 16 m/s
Solution: N = mv²/r supplies the wall reaction; friction μN ≥ mg ⇒ v_min = √(rg/μ) = √(6.4×10/0.4) = √160 ≈ 12.6 m/s.
Q6 — Banking of Roads & Well of Death · medium · numerical
A railway track of radius 200 m is banked so that a train at 20 m/s exerts no side thrust on the rails. tanθ equals:
A. 0.2 ✓ Correct
B. 0.4
C. 0.1
D. 0.05
Solution: tanθ = v²/rg = 400/2000 = 0.2.
Q7 — Banking of Roads & Well of Death · easy · numerical
A cyclist rounds a curve of radius 20 m at 10 m/s. The angle he must lean from the VERTICAL is:
A. tan⁻¹(0.2)
B. 30°
C. 45°
D. tan⁻¹(0.5) ≈ 26.6° ✓ Correct
Solution: tanθ = v²/rg = 100/200 = 0.5.
Q8 — Banking of Roads & Well of Death · medium · numerical
An aircraft banks its wings at 30° to fly a horizontal circle at 100 m/s (tan30° ≈ 0.577). The turn radius is about:
A. ≈ 1000 m
B. ≈ 1730 m ✓ Correct
C. ≈ 3000 m
D. ≈ 580 m
Solution: tanθ = v²/rg ⇒ r = v²/(g tanθ) = 10000/(10×0.577) ≈ 1732 m.