Acceleration — NEET Physics MCQs with Solutions
Free NEET Physics Acceleration MCQs with step-by-step solutions (36 questions). Part of Motion in 1 Dimension. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Acceleration · medium · theory
Acceleration is defined as
A. The rate of change of velocity ✓ Correct
B. The rate of change of distance
C. Velocity × time
D. The rate of change of position
Solution: $\vec a = \frac{d\vec v}{dt}$.
Q2 — Acceleration · medium · theory
The SI unit of acceleration is
A. m/s
B. N
C. m/s² ✓ Correct
D. m²/s
Solution: Change in velocity (m/s) per second gives m/s².
Q3 — Acceleration · medium · numerical
A car speeds up from $10$ m/s to $30$ m/s in $4$ s. Its acceleration is
A. $10$ m/s²
B. $5$ m/s² ✓ Correct
C. $7.5$ m/s²
D. $4$ m/s²
Solution: $a = \frac{30-10}{4} = 5$ m/s².
Q4 — Acceleration · medium · numerical
A body starts at $5$ m/s with uniform acceleration $2$ m/s². Its velocity after $3$ s is ($v = u + at$)
A. $10$ m/s
B. $6$ m/s
C. $11$ m/s ✓ Correct
D. $16$ m/s
Solution: $v = 5 + 2\times3 = 11$ m/s.
Q5 — Acceleration · medium · theory
A body starts from rest with uniform acceleration $4$ m/s². The distance covered in $3$ s is ($s = ut + \frac{1}{2}at^2$)
A. $6$ m
B. $36$ m
C. $18$ m ✓ Correct
D. $12$ m
Solution: $s = 0 + \frac{1}{2}\times4\times9 = 18$ m.
Q6 — Acceleration · medium · numerical
A body starting from rest attains a velocity of $20$ m/s over a distance of $100$ m. Its uniform acceleration is ($v^2 = u^2 + 2as$)
A. $0.2$ m/s²
B. $2$ m/s² ✓ Correct
C. $5$ m/s²
D. $4$ m/s²
Solution: $400 = 0 + 2a(100) \Rightarrow a = 2$ m/s².
Q7 — Acceleration · medium · theory
With the same braking force, the stopping distance of a car is proportional to
A. The cube of its speed
B. The square root of its speed
C. Its speed
D. The square of its speed ✓ Correct
Solution: From $v^2 = 2as$: $s = \frac{v^2}{2a}$ — double the speed, four times the distance.
Q8 — Acceleration · medium · theory
A car doubles its speed. With the same braking deceleration, its stopping distance becomes
A. The same
B. $8$ times
C. $4$ times ✓ Correct
D. $2$ times
Solution: $s \propto v^2$: doubling $v$ quadruples the stopping distance.
Q9 — Acceleration · medium · numerical
A car slows from $20$ m/s to rest in $5$ s. Its acceleration is
A. $4$ m/s²
B. $-5$ m/s²
C. $-4$ m/s² ✓ Correct
D. $-20$ m/s²
Solution: $a = \frac{0-20}{5} = -4$ m/s² (retardation of 4 m/s²).
Q10 — Acceleration · medium · theory
A body starts from rest with acceleration $2$ m/s². The distance covered in the $5$th second is $\left(s_n = u + \frac{a}{2}(2n-1)\right)$
A. $25$ m
B. $9$ m ✓ Correct
C. $5$ m
D. $10$ m
Solution: $s_5 = 0 + \frac{2}{2}(2\times5 - 1) = 9$ m.
Q11 — Acceleration · easy · theory
The slope of a velocity–time graph gives
A. Acceleration ✓ Correct
B. Speed
C. Distance
D. Displacement
Solution: $a = \frac{dv}{dt}$ — the slope of $v$ against $t$.
Q12 — Acceleration · medium · theory
A body has uniform acceleration if its velocity changes by
A. Zero
B. Equal amounts in equal intervals of time ✓ Correct
C. Unequal amounts uniformly
D. Equal amounts in equal distances
Solution: Constant $a$ means the same $\Delta v$ every second.
Q13 — Acceleration · easy · theory
A body is said to be decelerating (slowing down) when
A. Its velocity is negative
B. Its acceleration is opposite to its velocity ✓ Correct
C. Its acceleration is negative
D. Its acceleration is zero
Solution: Slowing down means $\vec a$ opposes $\vec v$ — the SIGN alone of $a$ doesn’t decide it.
Q14 — Acceleration · medium · numerical
The position of a particle is $x = t^3$ (metres, seconds). Its acceleration at $t = 2$ s is
A. $8$ m/s²
B. $4$ m/s²
C. $6$ m/s²
D. $12$ m/s² ✓ Correct
Solution: $v = 3t^2$, $a = 6t$; at $t=2$: $a = 12$ m/s².
Q15 — Acceleration · medium · numerical
The velocity of a particle is $v = 3t^2$ (m/s, seconds). Its acceleration at $t = 1$ s is
A. $3$ m/s²
B. $6$ m/s² ✓ Correct
C. $9$ m/s²
D. $1$ m/s²
Solution: $a = \frac{dv}{dt} = 6t$; at $t=1$: $6$ m/s².
Q16 — Acceleration · medium · theory
A ball is thrown straight up. During its ENTIRE flight (ignoring air), its acceleration is
A. Zero at the top
B. $g$ downward throughout ✓ Correct
C. $g$ upward while rising
D. Changing continuously
Solution: Gravity acts the same at all times — even at the top where velocity is momentarily zero.
Q17 — Acceleration · medium · theory
If the acceleration of a body is zero, its motion is
A. Circular
B. Impossible
C. Uniformly accelerated
D. Uniform velocity (or rest) ✓ Correct
Solution: No acceleration means velocity never changes.
Q18 — Acceleration · easy · theory
A body moving at $10$ m/s decelerates uniformly at $2$ m/s². The time it takes to stop is
A. $20$ s
B. $2$ s
C. $10$ s
D. $5$ s ✓ Correct
Solution: $0 = 10 - 2t \Rightarrow t = 5$ s.
Q19 — Acceleration · medium · theory
A body moving at $10$ m/s decelerates uniformly at $2$ m/s². The distance it covers before stopping is
A. $50$ m
B. $10$ m
C. $5$ m
D. $25$ m ✓ Correct
Solution: $0 = 100 - 2(2)s \Rightarrow s = 25$ m.
Q20 — Acceleration · medium · numerical
A train speeds up from $36$ km/h to $72$ km/h in $10$ s. Its acceleration is
A. $1$ m/s² ✓ Correct
B. $0.5$ m/s²
C. $2$ m/s²
D. $3.6$ m/s²
Solution: Convert: $10$ m/s $\to 20$ m/s. $a = \frac{20-10}{10} = 1$ m/s².
Q21 — Acceleration · medium · theory
Can the speed of a body increase while its acceleration is decreasing?
A. Yes — as long as acceleration stays in the direction of motion ✓ Correct
B. Only in free fall
C. Only if velocity is negative
D. No, never
Solution: A shrinking but still-forward acceleration keeps adding speed, just more slowly.
Q22 — Acceleration · medium · theory
A particle has positive velocity and constant negative acceleration. It is currently
A. At rest
B. Speeding up
C. Slowing down ✓ Correct
D. Moving with uniform velocity
Solution: Acceleration opposite to velocity always means slowing down.
Q23 — Acceleration · medium · numerical
A body starts from rest with uniform acceleration. The ratio of distances covered in the 1st, 2nd and 3rd seconds is
A. $1:1:1$
B. $1:2:3$
C. $1:3:5$ ✓ Correct
D. $1:4:9$
Solution: Distances in successive seconds follow the odd numbers (Galileo’s rule): $1:3:5:7\ldots$
Q24 — Acceleration · medium · theory
The area under an acceleration–time graph gives
A. Displacement
B. Distance
C. Average speed
D. Change in velocity ✓ Correct
Solution: $\int a\,dt = \Delta v$.
Q25 — Acceleration · medium · numerical
A body starts from rest with uniform acceleration and covers $16$ m in $2$ s. Its acceleration is
A. $2$ m/s²
B. $8$ m/s² ✓ Correct
C. $4$ m/s²
D. $16$ m/s²
Solution: $16 = \frac{1}{2}a(4) \Rightarrow a = 8$ m/s².
Q26 — Acceleration · medium · numerical
A body starts from rest with uniform acceleration. The ratio of its velocities at times $t$ and $2t$ is
A. $1:2$ ✓ Correct
B. $2:1$
C. $1:\sqrt{2}$
D. $1:4$
Solution: $v = at \propto t$: at double the time, double the velocity.
Q27 — Acceleration · medium · theory
A body moving with constant (non-zero) acceleration can
A. Reverse its direction of motion ✓ Correct
B. Not have zero velocity
C. Never change direction
D. Only move in a straight line forever
Solution: Example: a ball thrown upward — constant $g$ downward, yet the motion reverses at the top.
Q28 — Acceleration · medium · theory
For uniformly accelerated motion, the average velocity over an interval equals
A. $v - u$
B. $\sqrt{uv}$
C. $\frac{u+v}{2}$ ✓ Correct
D. $\frac{2uv}{u+v}$
Solution: Velocity changes linearly with time, so the average is the mean of the initial and final values.
Q29 — Acceleration · medium · theory
A particle starts at $20$ m/s with acceleration $-10$ m/s². Its velocity at $t = 3$ s is
A. $-10$ m/s (10 m/s in the reverse direction) ✓ Correct
B. $10$ m/s
C. $-30$ m/s
D. Zero
Solution: $v = 20 - 10\times3 = -10$ m/s — it stopped at $t=2$ s and reversed.
Q30 — Acceleration · medium · theory
The dimensional formula of acceleration is
A. $[MLT^{-2}]$
B. $[LT^{-1}]$
C. $[LT^{-2}]$ ✓ Correct
D. $[L^2T^{-2}]$
Solution: Velocity per time: $[LT^{-1}]/[T] = [LT^{-2}]$.