Velocity — NEET Physics MCQs with Solutions
Free NEET Physics Velocity MCQs with step-by-step solutions (36 questions). Part of Motion in 1 Dimension. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Velocity · easy · theory
Velocity is a
A. Scalar quantity
B. Vector quantity ✓ Correct
C. Pure number
D. Unit
Solution: Velocity is speed WITH direction — a vector.
Q2 — Velocity · easy · theory
Average velocity is defined as
A. Distance ÷ time
B. Speed × time
C. Displacement ÷ time ✓ Correct
D. Acceleration × time
Solution: $\bar{\vec v} = \frac{\Delta\vec r}{\Delta t}$ — it uses displacement, not path length.
Q3 — Velocity · medium · theory
A jogger returns to her starting point after a $30$-minute run. Her average velocity is
A. Maximum
B. Equal to her average speed
C. Zero ✓ Correct
D. Negative
Solution: Round trip $\Rightarrow$ zero displacement $\Rightarrow$ zero average velocity (average speed is non-zero).
Q4 — Velocity · easy · theory
Instantaneous velocity is given by
A. $\frac{d^2x}{dt^2}$
B. $\frac{dx}{dt}$ ✓ Correct
C. $x\cdot t$
D. $\frac{x}{t}$
Solution: Velocity is the time derivative of position.
Q5 — Velocity · easy · numerical
The position of a particle is $x = 3t^2$ (metres, seconds). Its velocity at $t = 2$ s is
A. $6$ m/s
B. $24$ m/s
C. $3$ m/s
D. $12$ m/s ✓ Correct
Solution: $v = \frac{dx}{dt} = 6t$; at $t = 2$: $v = 12$ m/s.
Q6 — Velocity · easy · theory
A body moving with uniform velocity has
A. Zero acceleration ✓ Correct
B. Changing direction
C. Constant non-zero acceleration
D. Increasing speed
Solution: Uniform velocity means neither the magnitude nor direction changes — so $a = 0$.
Q7 — Velocity · easy · theory
In one-dimensional motion, velocity
A. Can be positive, negative or zero ✓ Correct
B. Cannot be zero
C. Is always equal to speed
D. Is always positive
Solution: The sign encodes direction along the axis.
Q8 — Velocity · easy · numerical
The position of a particle is $x = 5 + 4t$ (metres, seconds). Its velocity is
A. $9$ m/s
B. $5$ m/s
C. $4$ m/s ✓ Correct
D. $20$ m/s
Solution: $v = \frac{dx}{dt} = 4$ m/s — uniform velocity (the 5 m is just the starting position).
Q9 — Velocity · medium · theory
The magnitude of average velocity compared with average speed is
A. Less than or equal to it ✓ Correct
B. Always double
C. Greater than or equal to it
D. Always equal
Solution: $|\bar{\vec v}| = \frac{|\text{displacement}|}{t} \leq \frac{\text{distance}}{t} = $ average speed.
Q10 — Velocity · easy · theory
Can the velocity of a body change while its speed remains constant?
A. No, never
B. Only if it accelerates in a straight line
C. Only at rest
D. Yes — if the direction changes (e.g. circular motion) ✓ Correct
Solution: Velocity is a vector: changing direction alone changes velocity.
Q11 — Velocity · medium · theory
Two trains run at $60$ km/h and $40$ km/h in OPPOSITE directions. The magnitude of their relative velocity is
A. $20$ km/h
B. $2400$ km/h
C. $50$ km/h
D. $100$ km/h ✓ Correct
Solution: Opposite directions: relative speed $= 60 + 40 = 100$ km/h.
Q12 — Velocity · medium · theory
Two cars travel in the same direction at $80$ km/h and $50$ km/h. The velocity of the faster car relative to the slower one is
A. $30$ km/h forward ✓ Correct
B. Zero
C. $130$ km/h
D. $30$ km/h backward
Solution: $\vec v_{rel} = 80 - 50 = 30$ km/h in the direction of motion.
Q13 — Velocity · easy · theory
A particle moves as $x = t^3 - 3t^2$ (metres, seconds). Its velocity is zero at the non-zero time $t =$
A. $1.5$ s
B. $3$ s
C. $1$ s
D. $2$ s ✓ Correct
Solution: $v = 3t^2 - 6t = 3t(t-2) = 0 \Rightarrow t = 0$ or $t = 2$ s.
Q14 — Velocity · medium · theory
A particle at rest necessarily has
A. All of these zero
B. Zero position
C. Zero acceleration
D. Zero velocity ✓ Correct
Solution: Rest means velocity zero; its position can be anywhere, and acceleration may even be non-zero momentarily.
Q15 — Velocity · easy · numerical
A body moves at $5$ m/s for $10$ s, then stays at rest for $10$ s (no reversal). Its average velocity over the $20$ s is
A. Zero
B. $1$ m/s
C. $5$ m/s
D. $2.5$ m/s ✓ Correct
Solution: Displacement $= 50$ m in $20$ s: $\bar v = 2.5$ m/s.
Q16 — Velocity · easy · theory
A negative velocity in one-dimensional motion means the particle is
A. Slowing down
B. At rest
C. Moving in the negative direction of the axis ✓ Correct
D. Accelerating
Solution: The sign of $v$ gives direction only — it says nothing about speeding up or slowing down.
Q17 — Velocity · easy · theory
A car moving east at $40$ km/h turns around and moves west at $40$ km/h. The magnitude of its change in velocity is
A. $80$ km/h ✓ Correct
B. $40\sqrt{2}$ km/h
C. $40$ km/h
D. Zero
Solution: $\Delta v = (-40) - (+40) = -80$: magnitude $80$ km/h, directed west.
Q18 — Velocity · easy · theory
The slope of the tangent to a position–time graph at an instant gives
A. Average velocity
B. Distance
C. Instantaneous velocity ✓ Correct
D. Acceleration
Solution: $v = \frac{dx}{dt}$ — geometrically the slope of the tangent at that point.
Q19 — Velocity · easy · numerical
A man walks $100$ m east in $50$ s, then $100$ m west in $50$ s. His average velocity for the whole trip is
A. $2$ m/s
B. $1$ m/s
C. Zero ✓ Correct
D. $4$ m/s
Solution: Net displacement is zero, so average velocity $= 0$ (average speed is 2 m/s).
Q20 — Velocity · easy · theory
A body has uniform velocity if it covers
A. Equal distances in unequal times
B. Increasing displacements
C. Equal displacements in equal intervals of time ✓ Correct
D. Equal distances only
Solution: Uniform velocity: same displacement (magnitude AND direction) every equal time interval.
Q21 — Velocity · medium · theory
The SI unit of velocity is
A. m/s²
B. m
C. km/h
D. m/s ✓ Correct
Solution: Metre per second; km/h is common but not the SI unit.
Q22 — Velocity · easy · theory
A lift ascends $10$ m in $5$ s at constant rate. Its velocity is
A. $2$ m/s upward ✓ Correct
B. $50$ m/s
C. $0.5$ m/s
D. $2$ m/s downward
Solution: $v = \frac{10}{5} = 2$ m/s, directed upward.
Q23 — Velocity · easy · numerical
The position of a particle is $x = t^2 - 4t + 3$ (metres, seconds). Its velocity at $t = 1$ s is
A. Zero
B. $-4$ m/s
C. $-2$ m/s ✓ Correct
D. $2$ m/s
Solution: $v = 2t - 4$; at $t=1$: $v = -2$ m/s (moving in the negative direction).
Q24 — Velocity · easy · theory
Average velocity equals instantaneous velocity when the motion is
A. Uniformly accelerated
B. Any motion
C. Circular
D. Uniform (constant velocity) ✓ Correct
Solution: With constant velocity, every instant matches the average.
Q25 — Velocity · medium · theory
Two cars approach each other at $30$ km/h and $20$ km/h. Their relative speed of approach is
A. $600$ km/h
B. $50$ km/h ✓ Correct
C. $25$ km/h
D. $10$ km/h
Solution: Head-on approach: speeds add, $30+20 = 50$ km/h.
Q26 — Velocity · easy · theory
A body moves with constant velocity $20$ m/s for $3$ s. Its displacement is
A. $6.7$ m
B. $20$ m
C. $23$ m
D. $60$ m ✓ Correct
Solution: $s = vt = 20\times3 = 60$ m.
Q27 — Velocity · easy · theory
A position–time graph with negative slope indicates
A. Velocity in the negative direction ✓ Correct
B. The body at rest
C. Impossible motion
D. Negative acceleration
Solution: Slope of $x$–$t$ IS velocity; a negative slope means $x$ is decreasing.
Q28 — Velocity · easy · theory
A particle reverses its direction of motion at the instant when
A. Its position is zero
B. Its speed is maximum
C. Its velocity changes sign ✓ Correct
D. Its acceleration is zero
Solution: Direction reversal is exactly a sign change of velocity (passing through zero).
Q29 — Velocity · medium · theory
Can a body have zero velocity and non-zero acceleration at the same instant?
A. Only at rest permanently
B. Only in circular motion
C. No, never
D. Yes — e.g. at the top of a vertical throw ✓ Correct
Solution: At the highest point $v = 0$ momentarily while $a = g$ still acts — the classic example.
Q30 — Velocity · medium · numerical
A particle covers displacement $\vec d_1 = 3\hat{i}$ m in $1$ s and then $\vec d_2 = 4\hat{j}$ m in the next $1$ s. The magnitude of its average velocity over the $2$ s is
A. $2.5$ m/s ✓ Correct
B. $3.5$ m/s
C. $5$ m/s
D. $7$ m/s
Solution: Total displacement $= \sqrt{9+16} = 5$ m in $2$ s $\Rightarrow 2.5$ m/s.