Addition and Subtraction — NEET Physics MCQs with Solutions
Free NEET Physics Addition and Subtraction MCQs with step-by-step solutions (71 questions). Part of Vectors. Practise online on Prepizo — no login needed.
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Questions with solutions
Q1 — Addition and Subtraction · easy
There are two force vectors, one of 5 N and other of 12 N. If the resultant of the two forces has a magnitude of 17 N, 7 N and 13 N respectively, at what angle the two vectors be added to get these resultants?
A. 0°, 180° and 90° ✓ Correct
B. 0°, 90° and 180°
C. 0°, 90° and 90°
D. 180°, 0° and 90°
Solution: For resultant = 17 N (max), angle = 0°. For resultant = 7 N (min), angle = 180°. For resultant = 13 N, angle = 90°.
Q2 — Addition and Subtraction · medium
If $\vec{A} = 4\hat{i} + 3\hat{j}$ and $\vec{B} = 6\hat{i} + 8\hat{j}$, then magnitude and direction of $\vec{A} - \vec{B}$ will be
A. $5, \tan^{-1}(3/4)$
B. $5\sqrt{5}, \tan^{-1}(1/2)$ ✓ Correct
C. $10, \tan^{-1}(5)$
D. $25, \tan^{-1}(3/4)$
Solution: $\vec{A} - \vec{B} = -2\hat{i} - 5\hat{j}$. Magnitude = $\sqrt{4 + 25} = \sqrt{29}$. Direction = $\tan^{-1}(5/2)$.
Q3 — Addition and Subtraction · medium
A truck travelling due north at 20 m/s turns west and travels at the same speed. The change in its velocity is
A. $40$ m/s N–W
B. $20\sqrt{2}$ m/s N–W ✓ Correct
C. $40$ m/s S–W
D. $20\sqrt{2}$ m/s S–W
Solution: Initial velocity = 20 m/s north, Final = 20 m/s west. Change = $\sqrt{20^2 + 20^2} = 20\sqrt{2}$ in N-W direction.
Q4 — Addition and Subtraction · medium
If the sum of two unit vectors is a unit vector, then magnitude of difference is
A. $\sqrt{2}$
B. $\sqrt{3}$ ✓ Correct
C. $1/\sqrt{2}$
D. $\sqrt{5}$
Solution: For two unit vectors with sum as unit vector, angle between them is 120°. Difference magnitude = $\sqrt{3}$.
Q5 — Addition and Subtraction · medium
If $\vec{A} = 2\hat{i} - \hat{j}$, $\vec{B} = 3\hat{j} - \hat{k}$ and $\vec{C} = 6\hat{i} - 2\hat{k}$, Value of $\vec{A} + 2\vec{B} - 3\vec{C}$ would be
A. $-20\hat{i} + 5\hat{j} + 4\hat{k}$
B. $-20\hat{i} + 5\hat{j} - 4\hat{k}$ ✓ Correct
C. $4\hat{i} - 5\hat{j} - 20\hat{k}$
D. $5\hat{i} - 4\hat{j} - 10\hat{k}$
Solution: $\vec{A} + 2\vec{B} - 3\vec{C} = 2\hat{i} - \hat{j} + 6\hat{j} - 2\hat{k} - 18\hat{i} + 6\hat{k} = -20\hat{i} + 5\hat{j} + 4\hat{k}$.
Q6 — Addition and Subtraction · hard
An object of m kg with speed of v m/s strikes a wall at an angle θ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will be
A. 0
B. mv
C. mv/2
D. $2mv\sin\theta$ ✓ Correct
Solution: Change in momentum = $2mv\sin\theta$ (perpendicular component changes sign).
Q7 — Addition and Subtraction · medium
Two forces, each of magnitude F have a resultant of the same magnitude F. The angle between the two forces is
A. 45°
B. 120° ✓ Correct
C. 150°
D. 60°
Solution: For equal forces with resultant equal to F: $F^2 = F^2 + F^2 + 2F^2\cos\theta$. This gives $\cos\theta = -1/2$, so $\theta = 120°$.
Q8 — Addition and Subtraction · easy
For the resultant of the two vectors to be maximum, what must be the angle between them
A. 0° ✓ Correct
B. 60°
C. 90°
D. 180°
Solution: Resultant is maximum when vectors are parallel (angle = 0°).
Q9 — Addition and Subtraction · easy
A particle is simultaneously acted by two forces equal to 4 N and 3 N. The net force on the particle is
A. 7 N
B. 5 N
C. 1 N
D. Between 1 N and 7 N ✓ Correct
Solution: Resultant can vary from |4-3| = 1 N to 4+3 = 7 N depending on angle.
Q10 — Addition and Subtraction · medium
A particle is simultaneously acted by two forces of 4 N and 3 N and then lies outside this plane. The resultant $\vec{A} + \vec{B} + \vec{C}$
A. Can be zero
B. Cannot be zero ✓ Correct
C. Lies in the plane containing AB
D. Lies in the plane containing C
Solution: If C lies outside the plane, the resultant cannot be zero.
Q11 — Addition and Subtraction · medium
If the resultant of two forces be smaller than the magnitude of larger force, the two forces must be
A. Different both in magnitude and direction ✓ Correct
B. Mutually perpendicular to one another
C. Possess extremely small magnitude
D. Point in opposite directions
Solution: Resultant less than larger force means they are not aligned and must be in different directions.
Q12 — Addition and Subtraction · easy
Forces $\vec{F}_1$ and $\vec{F}_2$ act on a point mass in two mutually perpendicular directions. The resultant force on the point mass will be
A. $F_1 + F_2$
B. $F_1 - F_2$
C. $\sqrt{F_1^2 + F_2^2}$ ✓ Correct
D. $\sqrt{F_1^2 - F_2^2}$
Solution: For perpendicular forces, resultant = $\sqrt{F_1^2 + F_2^2}$ (Pythagorean theorem).
Q13 — Addition and Subtraction · easy
If $|\vec{A} + \vec{B}| = |\vec{A}| + |\vec{B}|$, the angle between $\vec{A}$ and $\vec{B}$ is
A. 60°
B. 0° ✓ Correct
C. 120°
D. 90°
Solution: This equality holds only when vectors are parallel (0° angle).
Q14 — Addition and Subtraction · hard
Let the angle between two nonzero vectors $\vec{A}$ and $\vec{B}$ be 120° and resultant be $\vec{C}$
A. $C$ must be equal to $|A-B|$
B. $C$ must be less than $|A-B|$
C. $C$ must be greater than $|A-B|$ ✓ Correct
D. $C$ may be equal to $|A-B|$
Solution: For 120° angle, the resultant can be greater than the difference.
Q15 — Addition and Subtraction · easy
The magnitude of vectors $\vec{A}$, $\vec{B}$ and $\vec{C}$ are respectively 12, 5 and 13 units and $\vec{A} + \vec{B} = \vec{C}$, then the angle between $\vec{A}$ and $\vec{B}$ is
A. 90° ✓ Correct
B. 60°
C. 120°
D. 45°
Solution: Since $12^2 + 5^2 = 13^2$ (144 + 25 = 169), vectors are perpendicular.
Q16 — Addition and Subtraction · easy
Magnitude of vector which comes on addition of two vectors, $6\hat{i} + 7\hat{j}$ and $3\hat{i} + 4\hat{j}$ is
A. $\sqrt{136}$
B. $13.2$
C. $\sqrt{202}$ ✓ Correct
D. $\sqrt{160}$
Solution: Sum = $9\hat{i} + 11\hat{j}$. Magnitude = $\sqrt{81 + 121} = \sqrt{202}$.
Q17 — Addition and Subtraction · easy
A particle has displacement of 12 m towards east and 5 m towards north then 6 m vertically upward. The sum of these displacements is
A. 12 m
B. 10.04 m
C. 14.31 m ✓ Correct
D. None of these
Solution: Total displacement = $\sqrt{12^2 + 5^2 + 6^2} = \sqrt{144 + 25 + 36} = \sqrt{205} \approx 14.31$ m.
Q18 — Addition and Subtraction · medium
The three vectors $\vec{A} = 3\hat{i} + 2\hat{j} + \hat{k}$, $\vec{B} = \hat{i} + 3\hat{j} + 5\hat{k}$ and $\vec{C} = 2\hat{i} + \hat{j} + 4\hat{k}$ form
A. An equilateral triangle
B. Isosceles triangle
C. A right angled triangle ✓ Correct
D. No triangle
Solution: $|A|^2 = 14$, $|B|^2 = 35$, $|C|^2 = 21$. Since $14 + 21 = 35$, it forms a right triangle.
Q19 — Addition and Subtraction · easy
For the figure shown, $\vec{A} + \vec{B}$ equals
A. $\vec{C}$ ✓ Correct
B. $\vec{B} + \vec{C}$
C. $\vec{C} + \vec{A}$
D. $\vec{A} + \vec{B} + \vec{C} = 0$
Solution: From the vector diagram, $\vec{A} + \vec{B} = \vec{C}$.
Q20 — Addition and Subtraction · medium
Let $\vec{C} = \vec{A} + \vec{B}$, then
A. $|C|$ is always greater than $|A|$
B. It is possible to have $|C| < |A|$ and $|C| < |B|$ ✓ Correct
C. $C$ is always equal to $A + B$
D. $C$ is never equal to $A + B$
Solution: When vectors are opposite, $|C|$ can be less than both $|A|$ and $|B|$.
Q21 — Addition and Subtraction · easy
The value of the sum of two vectors $\vec{A}$ and $\vec{B}$ with θ as the angle between them is
A. $\sqrt{A^2 + B^2 + 2AB\cos\theta}$ ✓ Correct
B. $\sqrt{A^2 + B^2 - 2AB\cos\theta}$
C. $\sqrt{A^2 + B^2 + 2AB\sin\theta}$
D. $\sqrt{A^2 + B^2 - 2AB\sin\theta}$
Solution: This is the law of cosines for vector addition.
Q22 — Addition and Subtraction · medium
Following sets of three forces act on a body. Whose resultant cannot be zero
A. 10, 10, 10
B. 10, 10, 20
C. 10, 20, 23 ✓ Correct
D. 10, 20, 40
Solution: For three forces to balance, sum of any two must be ≥ third. Here 10 + 20 < 23.
Q23 — Addition and Subtraction · medium
When three forces of 50 N, 30 N and 15 N act on a body, then the body is
A. At rest
B. Moving with a uniform velocity
C. In equilibrium
D. Moving with an acceleration ✓ Correct
Solution: Since 50 + 30 > 15 and 50 + 15 > 30, the forces cannot balance. Net force exists.
Q24 — Addition and Subtraction · hard
The sum of two forces acting at a point is 16 N. If the resultant force is 8 N and its direction is perpendicular to minimum force then the forces are
A. 6 N and 10 N ✓ Correct
B. 8 N and 8 N
C. 4 N and 12 N
D. 2 N and 14 N
Solution: Let forces be A and B. A + B = 16 and resultant R = 8. Using vector diagram analysis: A = 6 N, B = 10 N.
Q25 — Addition and Subtraction · medium
If vectors $\vec{P}$, $\vec{Q}$ and $\vec{R}$ have magnitude 5, 12 and 13 units and $\vec{P} + \vec{Q} = \vec{R}$, the angle between $\vec{Q}$ and $\vec{R}$ is
A. $\cos^{-1}(5/12)$
B. $\cos^{-1}(5/13)$ ✓ Correct
C. $\cos^{-1}(12/13)$
D. $\cos^{-1}(7/13)$
Solution: Since $5^2 + 12^2 = 13^2$, angle between P and Q is 90°. Using cosine formula: $\cos\theta = 12/13$ between Q and R.
Q26 — Addition and Subtraction · hard
The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to the vector $\vec{A}$ and its magnitude is equal to half the magnitude of vector $\vec{B}$. The angle between $\vec{A}$ and $\vec{B}$ is
A. 120°
B. 150° ✓ Correct
C. 135°
D. None of these
Solution: Using perpendicularity condition and magnitude relation: angle = 150°.
Q27 — Addition and Subtraction · medium
What vector must be added to the two vectors $\hat{i} + 2\hat{j} + 2\hat{k}$ and $2\hat{i} + \hat{j} - \hat{k}$, so that the resultant may be a unit vector along x-axis
A. $-2\hat{i} - \hat{j} + \hat{k}$
B. $-2\hat{i} + \hat{j} - \hat{k}$ ✓ Correct
C. $-2\hat{i} - \hat{j} - \hat{k}$
D. $2\hat{i} - \hat{j} - \hat{k}$
Solution: Sum of first two = $3\hat{i} + 3\hat{j} + \hat{k}$. To get $\hat{i}$, add $-2\hat{i} - 3\hat{j} - \hat{k}$.
Q28 — Addition and Subtraction · medium
What is the angle between $\vec{P}$ and the resultant of $(\vec{P} + \vec{Q})$ and $(\vec{P} - \vec{Q})$
A. Zero ✓ Correct
B. $\tan^{-1}(P/Q)$
C. $\tan^{-1}(Q/P)$
D. $\tan^{-1}(P+Q)/(P-Q)$
Solution: Resultant of $(\vec{P} + \vec{Q})$ and $(\vec{P} - \vec{Q})$ is $2\vec{P}$, which is parallel to $\vec{P}$.
Q29 — Addition and Subtraction · hard
The resultant of $\vec{P}$ and $\vec{Q}$ is perpendicular to $\vec{P}$. What is the angle between $\vec{P}$ and $\vec{Q}$
A. $\cos^{-1}(P/Q)$
B. $\cos^{-1}(-P/Q)$ ✓ Correct
C. $\sin^{-1}(P/Q)$
D. $\sin^{-1}(-P/Q)$
Solution: For perpendicular resultant: $\cos\theta = -P/Q$.
Q30 — Addition and Subtraction · medium
Maximum and minimum magnitudes of the resultant of two vectors of magnitudes P and Q are in the ratio 3:1. Which of the following relations is true
A. $P = 2Q$ ✓ Correct
B. $P = Q$
C. $PQ = 1$
D. None of these
Solution: Max = P+Q, Min = |P-Q|. If (P+Q)/(P-Q) = 3, then P = 2Q.